Answer:
a
Step-by-step explanation:
that is the answer
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer:
mLNM=63
Step-by-step explanation:
triangle JKL is isocelese so mKJL and KLJ are the same
180-72=108
108/2=54
so both mKLJ and mMLN are equal
and since triangle LMN is an isoceles then mLNM and mLMN are equal to each other
so 180-54=126
126/2=63
mLNM=63
Answer:
take a picture of it and then put it up
Step-by-step explanation:
and they should give you the answer
Answer:
A and D
Step-by-step explanation:
One side-base right triangle and one angle-based right triangle.
