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Simora [160]
3 years ago
13

Hello I need help with this assignment and with the topic which is on Transformations if you could please help me

Mathematics
1 answer:
Norma-Jean [14]3 years ago
7 0
Is this an assignment I can not see what the question is or what you need help with
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What is the value of x? The figure is not drawn to scale. Show work
Alecsey [184]

Answer:

x = 21.

Step-by-step explanation:

AS there are parallel lines:

4/12 = 7/x

4x = 84

x = 84/4 = 21.

8 0
2 years ago
Which of the following statements is false?
Irina18 [472]

Answer:

6.5<6.05, this one is false

Step-by-step explanation:

look at the Statement and the numbers, it is false through my calculation

7 0
3 years ago
Approximate the area between the xxx-axis and h(x) = \dfrac{1}{7-x}h(x)= 7−x 1 ​ h, (, x, ), equals, start fraction, 1, divided
tiny-mole [99]

Answer:

\dfrac{47}{60} sq. units.

Step-by-step explanation:

The given function is

h(x)=\dfrac{1}{7-x}

We need to find the area between x-axis and the given function from x=2 to x=5.

Left Riemann sum formula of area:

Area=\sum_{n=0}^{N-1}f(x_n)(\Delta x_n)

For given question,

Area=\sum_{n=2}^{5-1}f(x_n)(\Delta x_n)

Area=\sum_{n=2}^{4}f(x_n)(\Delta x_n)

Area=f(x_2)(3-2)+f(x_3)(4-3)+f(x_4)(5-4)

Now,

Area=\dfrac{1}{7-2}\times (1)+\dfrac{1}{7-3}\times (1)+\dfrac{1}{7-4}\times (1)

Area=\dfrac{1}{5}+\dfrac{1}{4}+\dfrac{1}{3}

Area=\dfrac{12+15+20}{60}

Area=\dfrac{47}{60}

Therefore, the required area is \dfrac{47}{60} sq. units.

5 0
3 years ago
Please help asap 30 pts
tatiyna
B. By solving for x, you get x=8.39,x=-2.39.
5 0
4 years ago
The number N of cars produced at a certain factory in 1 day after t hours of operation is given by Upper N (t )equals 800 t minu
Elden [556K]

Answer:

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

Step-by-step explanation:

The function N(t) = 800 t -  5t², represents the number of cars produced at a time t hours in a day, where 0 ≤ t ≤ 10

The function C(N) = 30,000 + 8,000 N, represents the cost C​ (in dollars) of producing N cars

We need to find The cost C as a function of the time t

That means Substitute N in C by its function by other word find the composite function (C о N)(t)

∵ C(N) = 30,000 + 8,000 N

∵ N(t) = 800 t - 5 t²

- Substitute N in C by 800 t - 5 t²

∴ C(N(t)) = 30,000 + 8000(800 t - 5 t²)

- Multiply the bracket by 8000

∴ C(N(t)) = 30,000 + 8000(800 t) - 8000(5 t²)

∴ C(N(t)) = 30,000 + 6,400,000 t - 40,000 t²

- C(N(t) = C(t)

∴ C(t) = 30,000 + 6,400,000 t - 40,000 t²

The cost C as a function of t is C(t) = 30,000 + 6,400,000 t - 40,000 t²

5 0
3 years ago
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