HELP PLSSSS I DONT UNDERSTAND WALLAH

HELP ASAP I WILL GIVE 20 POINTS HELPPPPPPPPPPPP

Nikolay [14]

52s + 30b because 52 x s + 30 x b = 52s + 30b

6 0

2 years ago

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Equivalent to 4^7•4^-5

nekit [7.7K]

Answer:

Step-by-step explanation:

$\text{Use}\ a^n\cdot a^m=a^{n+m}\\\\4^7\cdot4^{-5}=4^{7+(-5)}=4^{7-5}=4^2=4\cdot4=16$

3 0

3 years ago

14/15 minus 1/3 as a fraction in simplest form

eduard

First step: Create a common denominator with 1/3

1/3 x 5/5 = 5/15

Second step: Subtract

14/15

-5/15

_____

a: 9/15

4 0

3 years ago

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Define z_alpha to be a z-score with an area of alpha to the right. For Example: z_0.10 means P(Z > z_0.10) = 0.10. We would a

Reptile [31]

Answer:

a) P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

And for this case the two values are : $z_{crit}= \pm 1.96$

b) P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates $\alpha/2$ of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

c) For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got $z_{\alpha/2}=1.64$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Part a

P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

And for this case the two values are : $z_{crit}= \pm 1.96$

Part b

P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates $\alpha/2$ of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

Part c

For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got $z_{\alpha/2}=1.64$

6 0

3 years ago

How does 1/12 - 5/6 = 9/12 um tring to learn how to add this like ?

tekilochka [14]

Answer:

see below

Step-by-step explanation:

1/12 - 5/6 = -9/12

We need to get a common denominator of 12

1/12 - 5/6*2/2 = -9 /12

1/12 - 10/12 = -9/12

Since the denominators are the same, we can subtract the numerators

1-10 = -9

-9/12 = - 9/12

We can simplify -9/12 by dividing the top and bottom by 3

-9/3 = -3

12 /3 = 4

-9/12 = -3/4

6 0

2 years ago

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