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lys-0071 [83]
3 years ago
8

What is the answer to this promblem

Mathematics
2 answers:
galina1969 [7]3 years ago
7 0

9514 1404 393

Answer:

  • to eliminate x: multiply the first by 3, and the second by -4
  • to eliminate y: multiply the first by 2, and the second by 5

Step-by-step explanation:

Pick the variable you want to eliminate. Determine the coefficients of that variable in the two equations. Negate one of them. Multiply each equation by the coefficient that came from the other equation.

__

<u>To eliminate x</u>

The x-coefficients are 4 and 3. If we negate 4, then the resulting y-coefficient will be positive. We choose to multiply the first equation by 3, the second by -4.

Here is the result of adding those:

  3(4x +5y) -4(3x -2y) = 3(7) -4(-12)   ⇒   23y = 69

<u>To eliminate y</u>

The y-coefficients are 5 and -2. If we negate -2, then the resulting x-coefficient will be positive. We choose to multiply the first equation by 2 and the second by 5.

Here is the result of adding those:

  2(4x +5y) +5(3x -2y) = 2(7) +5(-12)   ⇒   23x = -46

Svetradugi [14.3K]3 years ago
6 0

Answer:

Step-by-step explanation:

to kill x: duplicate the primary by 3, and the moment by -4 to eliminate y: increase the primary by 2, and the moment by 5 Step-by-step explanation: Pick the variable you need to eliminate. Decide the coefficients of that variable within the two conditions. Refute one of them. Increase each condition by the coefficient that came from the other equation. __ To dispense with x The x-coefficients are 4 and 3. On the off chance that we invalidate 4, then the coming about y-coefficient will be positive. We select to increase the primary condition by 3, the moment by -4. Here is the result of including those: 3(4x +5y) -4(3x -2y) = 3(7) -4(-12) ⇒ 23y = 69 To dispose of y The y-coefficients are 5 and -2. If we nullify -2, at that point the coming about x-coefficient will be positive. We select to duplicate the primary condition by 2 and the moment by 5. Here is the result of including those: 2(4x +5y) +5(3x -2y) = 2(7) +5(-12) ⇒ 23x = -46

hope this helps

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In how many ways can a committee of three men and three women be formed from a group of eight men and seven women
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<h3>Answer:  1960 </h3>

==========================================================

Explanation:

Order doesn't matter when it comes to committees without rankings. Each person on the committee is of equal rank to anyone else. This means we'll use a combination instead of a permutation.

We have 8 men and 3 seats to fill for the men. Plug n = 8 and r = 3 into the nCr combination formula

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8 C 3 = (8!)/(3!*(8-3)!)

8 C 3 = (8!)/(3!*5!)

8 C 3 = (8*7*6*5*4*3*2*1)/((3*2*1)*(5*4*3*2*1))

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Through similar steps, you should plug n = 7 and r = 3 into the nCr combination formula to get 7 C 3 = 35. This means there are 35 ways to pick the three women from a pool of seven.

Overall, there are 56*35 = 1960 ways to select the entire committee of 3 men and 3 women (from a pool of 8 men and 7 women).

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