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lianna [129]
3 years ago
7

B is a subset of A g Let set A = {a, b, c} and let set B = {b, c, d} a. True b. False

Mathematics
1 answer:
xxMikexx [17]3 years ago
7 0

Answer:

False

Step-by-step explanation:

A subset is a set whose elements belong to another set

If B is a subset of A, B would contain elements of A

For example,  A = {a, b, c} and if B is a subset of A , B = { a, b}

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(50 points) need help.
tatiyna

Answer:

I believe it is 127ft²

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
3. A prop for the theater club’s play is constructed as a cone topped with a half-sphere. What is the volume of the prop? Round
Mariana [72]

The volume of the prop is calculated to be 2,712.96 cubic inches.

<u>Step-by-step explanation:</u>

Step 1:

The prop consists of a cone and a half-sphere on top. We will have to calculate the volumes of the cone and the half-sphere separately and then add them to obtain the total volume.

Step 2:

The volume of a cone is determined by multiplying  \frac{1}{3} with π, the square of the radius (r²) and height (h). Here we substitute π as 3.14. The radius is 9 inches and the height is 14 inches.

The volume of the cone :  V=\pi r^{2} \frac{h}{3} = 3.14 \times 9^{2} \times \frac{14}{3} = 1,186.92 cubic inches.

Step 3:

The area of a half-sphere is half of a full sphere. The volume of a sphere is given by multiplying  \frac{4}{3} with π and the cube of the radius (r³).

Here the radius is 9 inches. We take π as 3.14.

The volume of a full sphere =  V=\frac{4}{3} \pi r^{3} =  \frac{4}{3} \times 3.14 \times 9^{3} = 3,052.08 cubic inches.

The volume of the half-sphere =  \frac{3,052.08}{2} = 1,526.04 cubic inches.

Step 4:

The total volume = The volume of the cone + The volume of the half sphere,

The total volume = 1,186.92 + 1,526.04 = 2,712.96 cubic inches.

5 0
3 years ago
the sun shines on a flagpole, causing a shadow to be cast on the ground. the distance from the base of the pole to the tip of th
kobusy [5.1K]

Answer:

30.17feet high

Step-by-step explanation:

Given the following

the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)

angle of elevation = 38°

Required

Height of the flagpole (opposite)

Using the SOH CAH TOA identity

Sin theta = opposite/hypotenuse

Sin 38 = H/49

H = 49sin38

H = 49(0.6157)

H = 30.17feet

Hence the flagpole is 30.17feet high

7 0
2 years ago
Find the volume of the composite figure. Explain your thought, explain how your arrived at your answer. SHOW YOUR WORK FOR FULL
kobusy [5.1K]
We assume the composite figure is a cone of radius 10 inches and slant height 15 inches set atop a hemisphere of radius 10 inches.

The formula for the volume of a cone makes use of the height of the apex above the base, so we need to use the Pythagorean theorem to find that.
   h = √((15 in)² - (10 in)²) = √115 in

The volume of the conical part of the figure is then
   V = (1/3)Bh = (1/3)(π×(10 in)²×(√115 in) = (100π√115)/3 in³ ≈ 1122.994 in³


The volume of the hemispherical part of the figure is given by
   V = (2/3)π×r³ = (2/3)π×(10 in)³ = 2000π/3 in³ ≈ 2094.395 in³

Then the total volume of the figure is
   V = (volume of conical part) + (volume of hemispherical part)
   V = (100π√115)/3 in³ + 2000π/3 in³
   V = (100π/3)(20 + √115) in³
   V ≈ 3217.39 in³
4 0
2 years ago
Who can help me with number 14
Rzqust [24]
(Original Price $425.4)

$328 × 30% = 98.4
328 + 98.4 = $426.40
5 0
3 years ago
Read 2 more answers
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