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VMariaS [17]
3 years ago
7

Help help please!!!!!

Mathematics
1 answer:
zubka84 [21]3 years ago
8 0
NO HELP MEEEEEEEEEE also I can’t see the question
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The half-life of a newly discovered radioactive element is 30 seconds. To the nearest tenth of a second, how long will it take f
Alexeev081 [22]

Answer:

It will take about 109.3 seconds for nine grams of the element to decay to 0.72 grams.

Step-by-step explanation:

We can write a half-life function to model our function.

A half-life function has the form:

\displaystyle A=A_0\left(\frac{1}{2}\right)^{t/d}

Where <em>A₀</em> is the initial amount, <em>t</em> is the time that has passes (in this case seconds), <em>d</em> is the half-life, and <em>A</em> is the amount after <em>t</em> seconds.

Since the half-life of the element is 30 seconds, <em>d</em> = 30. Our initial sample has nine grams, so <em>A₀</em> is 9. Substitute:

\displaystyle A=9\left(\frac{1}{2}\right)^{t/30}

We want to find the time it will take for the element to decay to 0.72 grams. So, we can let <em>A</em> = 0.72 and solve for <em>t: </em>

<em />\displaystyle 0.72=9\left(\frac{1}{2}\right)^{t/30}<em />

Divide both sides by 9:

\displaystyle 0.08=\left(\frac{1}{2}\right)^{t/30}

We can take the natural log of both sides:

\displaystyle \ln(0.08)=\ln\left(\left(\frac{1}{2}\right)^{t/30}\right)

By logarithm properties:

\displaystyle \ln(0.08)=\frac{t}{30}\ln(0.5)

Solve for <em>t: </em>

<em />\displaystyle t=\frac{30\ln(0.08)}{\ln(0.5)}\approx109.3\text{ seconds}<em />

<em />

So, it will take about 109.3 seconds for nine grams of the element to decay to 0.72 grams.

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