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VMariaS [17]
3 years ago
7

Help help please!!!!!

Mathematics
1 answer:
zubka84 [21]3 years ago
8 0
NO HELP MEEEEEEEEEE also I can’t see the question
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In a certain​ region, about 11 ,000 people are needed to support a fire station. How many fire stations would you expect in a ci
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Step-by-step explanation:

There are an estimated 29,819 fire departments in the US Of these, 2,785 ... provided EMS service and advanced life support, and 11,559 (39%) of departments ... The authors would also like to thank the members of the NFPA staff who ... Figure 2 Number of Volunteer Firefighters and Rate per 1,000 Population. 4.

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What is the 6th term of this geometric sequence? 1,7,49,343
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Evaluate rg + 2d when r = 3, g = 5, and d = 2
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3 years ago
The average daily high temperature in June in LA is 77 degree F with a standard deviation of 5 degree F. Suppose that the temper
olasank [31]

Answer:

11.51% probability of observing an 83 degree F temperature or higher LA during a randomly chosen day in June

The coldest 10% of the days during June in LA have high temperatures of 70.6F or lower.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 77, \sigma = 5

What is the probability of observing an 83 degree F temperature or higher LA during a randomly chosen day in June?

This probability is 1 subtracted by the pvalue of Z when X = 83. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{83 - 77}{5}

Z = 1.2

Z = 1.2 has a pvalue of 0.8849.

1 - 0.8849 = 0.1151

11.51% probability of observing an 83 degree F temperature or higher LA during a randomly chosen day in June

How cold are the coldest 10% of the days during June in LA?

High temperatures of X or lower, in which X is found when Z has a pvalue of 0.1, so whn Z = -1.28

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 77}{5}

X - 77 = -1.28*5

X = 70.6

The coldest 10% of the days during June in LA have high temperatures of 70.6F or lower.

5 0
3 years ago
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