(8/a+4)+(10/b-6)
so common denominator is (a+4)(b-6)
=(8/a+4) *(b-6/b-6)+(10/b-6)*(a+4/a+4)
= 8(b-6) / (a+4)(b-6) + 10(a+4)/(a+4)(b-6)
4t ^ 2 - 16 ÷8 ÷ t - 2 ÷6
=(4t ^ 2)-(16 ÷8 ÷ t)-(2 ÷6)
=(4t ^ 2)-(2/t)-1/3
=4t ^ 2-2/t-1/3
Let the number of bags that he would have been used to put 3 kg of apples be x. Thus the number of bags that would be used to put 2kgs will therefore be (x+9), hence the total number of kgs the bags will hold will be given by:
3*x=3x kgs
2(x+9)=(2x+18) kgs
since the total weights are the same then:
2x+18=3x
hence
18=3x-2x
18=x
thus the number of bags required to put 3 kgs of apples will be 18. Thus the total Kgs of apples was:
3x
=3*18
=54 kgs
