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andrew11 [14]
2 years ago
10

Yes help please thxssssssssssssssssssssssssssss

Mathematics
2 answers:
Bad White [126]2 years ago
4 0

Answer:

7/12 hope this helps!!

Step-by-step explanation:

Charra [1.4K]2 years ago
3 0
Answer=7/20

If there’s 20 total and there’s 7 blue it should be 7/20
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Please answer this!!!​
kenny6666 [7]

Answer:

just try to work and ask your teacher okay  I have to find the key to it first

Step-by-step explanation:

3 0
2 years ago
Write the standard form of the equation of the circle with radius 7 and center (5,−7).
olya-2409 [2.1K]

Answer:

(x-5)^2+(y+7)^2=49

Step-by-step explanation:

Use (x-h)^2+(y-k)^2=r^2 for the equation of a circle in standard form with radius r and center (h,k). Therefore, the equation of the circle in standard form is (x-5)^2+(y+7)^2=49

4 0
2 years ago
Number 2 please sos
makvit [3.9K]
Take 2202 divide by 11, then multiply that by 3 & there's your answer.
3 0
3 years ago
What is the length of the unknown side of the right triangle?
DerKrebs [107]

Answer:

13

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean Theorem

a^2+b^2=c^2

where<em> a</em> and <em>b</em> are the legs and <em>c</em> is the hypotenuse.

We know that the legs are 5 and 12. We also know the hypotenuse is x, or unknown.

Substitute 5 in for <em>a</em>, 12 for <em>b, </em>and x for <em>c.</em>

<em />5^2+12^2=x^2<em />

Evaluate the exponents.

5^2 is the same as 5*5, which is 25.

12^2 is the same as 12*12, which is 144.

25+144=x^2

Add 25 and 144

169=x^2

We are trying to find out what <em>x</em> is. In order to do this, we have to get <em>x</em> alone. Since x is being squared, take the square root of both sides. The exponent and square root will cancel, leaving x by itself.

\sqrt{169} =\sqrt{x^2} \\\\\sqrt{169}=x\\13=x

The hypotenuse is 13.

4 0
2 years ago
Read 2 more answers
Select ALL statements that are true about the functionDomain: [1, 11]Domain: [0, 13]Domain: (0, 13)Range: (1, 11)Range: [1, 11]R
zzz [600]

Domain : [1 , 11] -------- True

Domain : [0, 13] ---------- False

Domain : ( 0, 13) ----------True

Range : (1, 11) ----------------False

Range : [1, 11] ----------------False

Range : [0 , 13]---------------True

Maximum: (10, 11) ----------- True

Maximum : (3, 1 ) -------------False

Minimum : (3 , 1 ) -------------True

Minimum : (10 , 11 ) -----------False

8 0
11 months ago
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