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3 years ago

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Three students ran ½ mile around a track. The table below lists the time each student took to run around the track. Complete the

table by calculating the average speed of each student in miles per hour.

1 answer:

tensa zangetsu [6.8K]3 years ago

7 0

We can’t answer we don’t have the image of the table.

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Literally worth 100 POINTS answer the question!!!! WILL AWARD BRAINLIEST but only if work is shown and answer is actually CORREC

True [87]

The answer is 9/16 (decimal form:0.5625)

Since you have a multiply 2 and a divide 2, they cancel each other out (so you can remove both)
(1/2)^2 + 1/4 + (1/4)^2

Simplify both fractions with exponents
1/4 + 1/4 + 1/16

Add both 1/4
2/4= 1/2

1/2 + 1/16 = 9/16

Please give brainliest!!

5 0

3 years ago

Read 2 more answers

Evaluate the expression 2r - 2 for 2 = 5.

lyudmila [28]

Upload a picture of ur question

6 0

4 years ago

I don’t understand how to proof Cpctc or answer the questions

n200080 [17]

I think that first you need to understand what CPCTC is used for.

Let's start with the definition of congruent triangles.

Definition of congruent triangles
Two triangles are congruent if each side of one triangle is congruent to a corresponding side of the other triangle and each angle of one triangle is congruent to a corresponding angle of the other triangle.

A definition works two ways.
1) If you are told the sides and angles of one triangle are congruent to the corresponding sides and angle of a second triangle, then you can conclude the triangles are congruent.
2) If you are told the triangles are congruent, then you can conclude 6 statements of congruence, 3 for sides and 3 for angles.

Now let's see what CPCTC is and how it works.
CPCTC stands for "corresponding parts of congruent triangles are congruent."
The way it works is this. You can prove triangles congruent by knowing fewer that 6 statements of congruence. You can use ASA, SAS, AAS, SSS, etc. Once you prove two triangles congruent, then by the definition of congruent triangles, there are 6 congruent statements. That is where CPCTC comes in. Once you prove the triangles congruent, then you can conclude two corresponding sides or two corresponding angles are congruent by CPCTC. These two corresponding parts were not involved in proving the triangles congruent.

Problem 1.

Statements                                        Reasons
1. Seg. AD perp. seg. BC               1. Given
2. <ADB & <ADC are right angles     2. Def. of perp. lines
3. <ADB is congr. <ADC                 3. All right angles are congruent
4. Seg. BD is congr. seg CD           4. Given
5. Seg. AD is congr. seg. AD        5. Congruence of segments is reflexive
6. Tr. ABD is congr. tr. ACD           6. SAS
7. Seg. AB is congr. seg. AC        7. CPCTC

4 0

3 years ago

Choose the equation that best represents the general form of the following expression.

Nuetrik [128]

Here is how we get the equation that best represents the general form of the given expression above.
Since we have a fraction, what we are going to do in order to eliminate it is to multiply both sides by 2. So this gives us x^2 = 14x.
Move 14x, and the final form would be x^2 -14x = 0.
Hope this is the answer that you are looking for.

4 0

4 years ago

According to Boyle's Law, if the temperature of a confined gas is held fixed, then the product of the pressure P and the volume

Bad White [126]

If <em>PV</em> = 800, then <em>P</em> can be written as a function of <em>V</em>,

<em>P(V)</em> = 800 / <em>V</em>

(a) The average rate of change of <em>P</em> as <em>V</em> increases from 200 to 250 in³ is then

(<em>P</em> (250) - <em>P</em> (200)) / (250 in³ - 200 in³) = (3.2 lb/in² - 4lb/in²) / (50 in³)

... = -0.016 (lb/in²)/in³

(Or -0.016 lb/in⁵, but I figure writing the rate as (units of pressure) per (unit volume) makes more sense.)

(b) We can also write <em>V</em> as a function of <em>P</em> :

<em>V(P)</em> = 800 / <em>P</em>

Take the derivative:

<em>V'(P)</em> = - 800 / <em>P</em>²

which immediately demonstrates that <em>V'(P)</em> ∝ 1 / <em>P</em>², as required. (The fish-looking symbol, ∝, means "is proportional to".)

If differentiating is supposed to be more involved, you can use the limit definition:

$V'(P)=\displaystyle\lim_{h\to0}\frac{V(P+h)-V(P)}h$

$V'(P)=\displaystyle\lim_{h\to0}\frac{\frac{800}{P+h}-\frac{800}P}h$

$V'(P)=\displaystyle\lim_{h\to0}\frac{\frac{800P-800(P+h)}{P(P+h)}}h$

$V'(P)=\displaystyle800\lim_{h\to0}\frac{-\frac h{P(P+h)}}h$

$V'(P)=\displaystyle-800\lim_{h\to0}\frac1{P(P+h)}=-\dfrac{800}{P^2}$

7 0

3 years ago