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NikAS [45]
1 year ago
14

Write the number for fourteen million eighty thousand.

Mathematics
2 answers:
kipiarov [429]1 year ago
8 0

Answer:

14,080,000

Step-by-step explanation:

where the 4 is is the millions place

where the 1 is is the 10 millions place

where the 8 is is the 10 thousands place

KatRina [158]1 year ago
4 0

Step-by-step explanation:

14080000 answer is please follow me ......

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Can someone help? I hate math so much lol I don’t understand
marishachu [46]

Answer:

±6

Step-by-step explanation:

Given the mathematical expression;

√36 < √42 < √49

But, √36 = 6 * 6 = 6²

√49 = 7 * 7 = 7²

Simplifying further, we would substitute the new values respectively;

±[6] < √42 < ±[7]

Therefore, evaluating √36 is equal to ±6.

8 0
3 years ago
Is there any systematic tendency for part-time college faculty to hold their students to different standards than do full-time f
alexandr1967 [171]

Answer:

H0 : μ1 - μ2 = 0

H1 : μ1 - μ2 ≠ 0

-1. 34

0.1837

Step-by-step explanation:

Full time :

n1 = 125

x1 = 2.7386

s1 = 0.65342

Part time :

n2 = 88

x2 = 2.8439

s2 = 0.49241

H0 : μ1 - μ2 = 0

H1 : μ1 - μ2 ≠ 0

Test statistic :

The test statistic :

(x1 - x2) / sqrt[(s1²/n1 + s2²/n2)]

(2.7386 - 2.8439) / sqrt[(0.65342²/125 + 0.49241²/88)]

−0.1053 / sqrt(0.0034156615712 + 0.0027553)

-0.1053 /0.0785554

= - 1.34

Test statistic = - 1.34

The Pvalue :

Using df = smaller n - 1 = 88 - 1 = 87

Pvalue from test statistic score ;

Pvalue = 0.1837

Pvalue > α ; We fail to reject the null and conclude that the GPA does not differ.

At α = 0.01 ; the result is insignificant

6 0
2 years ago
Find the exact value of the expressions
timama [110]

Answer:

here is your correct answer and listen question no four option are incorrect

4 0
2 years ago
Graph the exponential function<img src="https://tex.z-dn.net/?f=%20f%28x%29%3D%5Cfrac%7B1%7D%7B2%7D%5E%7Bx%7D%20%20" id="TexForm
tatyana61 [14]

f(x)=\left(\dfrac{1}{2}\right)^x\\\\for\ x=-3\to y=\left(\dfrac{1}{2}\right)^{-3}=2^3=8\to(-3,\ 8)\\\\for\ x=-2\to y=\left(\dfrac{1}{2}\right)^{-2}=2^2=4\to(-2,\ 4)\\\\for\ x=-1\to y=\left(\dfrac{1}{2}\right)^{-1}=2^1=2\to(-1,\ 2)\\\\for\ x=0\to y=\left(\dfrac{1}{2}\right)^0=1\to(0,\ 1)\\\\for\ x=1\to y=\left(\dfrac{1}{2}\right)^1=\dfrac{1}{2}\to\left(1,\ \dfrac{1}{2}\right)\\\\for\ x=2\to y=\left(\dfrac{1}{2}\right)^2=\dfrac{1}{4}

3 0
3 years ago
Can you help me please.
Snowcat [4.5K]
Hey I would try to use Photomath or Socratic they are both apps that are downloadable
6 0
3 years ago
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