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OlgaM077 [116]
3 years ago
10

Select the characteristics of a Base Transceiver Station:

Computers and Technology
1 answer:
Andru [333]3 years ago
8 0

Answer:

The correct answer to the following question is options A, B, and D.

Explanation:

Base Transceiver Station (BTS) is an apparatus that works wireless communication between the network and user equipment (UE - Mobile phones (handset), wireless network computers). Wireless technologies like wi-fi, GSM, CDMA, etc.

Some elements of BTS :

  • Radio base station
  • Tower/Mast
  • Duplexer
  • Transceiver unit (TRU)
  • Microwave

So the above are the elements of the BSA, then it also having the characteristics related to these elements like it definitely connects to a cell network, sends phone or mobile phone and microwave signals to cellular providers but it isn't able to send the signals to the recepients.

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A weak fuel to air mixture along with normal airflow through a turbine engine may result in?
Sladkaya [172]

Answer:

A weak fuel to air mixture along with normal airflow through a turbine engine may result in <u>a lean die out</u>.

Explanation:

Lean die out is a type of problem that may occur in the turbine. This may result in the weak fuel to air mixture. In case if the mixture of fuel and air is getting low due to some reasons like leakage of gas or low speed of engine may result in dangerous conditions such as fire or blast in the turbine. This is called lean die out. In the result of this problem, the turbine can be burn with the blast and may leads to causalities.

5 0
3 years ago
Q1). Write a python program to pass a list to a function and double the odd values and half even values of a list and display li
zepelin [54]

Answer:

\textsf{\large{\underline{Solution}:}}

The given problem is solved using language - Python.

def f(x):

   new_list=[]

   for i in x:

       if i%2==0:

           new_list.append(i//2)

       else:

           new_list.append(i*2)

   return new_list

   

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(my_list)

print('Modified List:',my_list)

\textsf{\large{\underline{Logic}:}}

  1. Create a new list.
  2. Iterate over the list passed into the function.
  3. Check if the element is even or not. If true, append half the value of element in the list.
  4. If false, append twice the value of the element in the list.
  5. At last, return the new list.

There is another way of doing this - By using map() function.

—————————————————————————————

def f(x):

   return list(map(lambda x:x//2 if x%2==0 else 2*x,x))

   

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(2my_list)

print('Modified List:',my_list)

—————————————————————————————

\textsf{\large{\underline{O{u}tput}:}}

Original List: [1, 2, 3, 4, 5]

Modified List: [2, 1, 6, 2, 10]

8 0
3 years ago
What are the ethical implications of online social media after someone has died?
ZanzabumX [31]
<span>Think about the things people might have wanted private, but after death they have no control.</span>
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3 years ago
Write an example method that overrides the operator to create a new book whose title is a concatenation of the titles of two boo
Anastasy [175]

next time m8 mmmmmdsaasd

5 0
3 years ago
3. The wildlife department has been feeding a special food to rainbow trout finger lings in a pond. A sample of the weight of 40
andrey2020 [161]

Answer:

1)  402.7 grams. This estimate is called the sample mean.

2)  (399.11, 406.29)

3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.

I am 99% sure that the value lies between 399.11 grams and 406.29 grams.

Explanation:

sample size (n) = 40, the mean weight (x)= 402.7 grams and the standard deviation (σ)=8.8 grams

1) The point estimated mean weight of the population is 402.7 grams. This estimate is called the sample mean.

2) c = 99% = 0.99

α = 1 - 0.99 = 0.01

\frac{\alpha }{2} =\frac{0.01}{2} =0.005.

The z score of 0.005 corresponds with the z score of 0.495 (0.5 - 0.005).

z_\frac{\alpha }{2} =2.58.

The margin of error (e) = z_\frac{\alpha }{2}*\frac{\sigma}{\sqrt{n} }  =2.58*\frac{8.8}{\sqrt{40} } =3.59

The confidence interval = x ± e = 402.7 ± 3.59 = (399.11, 406.29)

3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.

I am 99% sure that the value lies between 399.11 grams and 406.29 grams.

8 0
3 years ago
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