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weqwewe [10]
3 years ago
8

The coordinate grid shows points A through K Which points are solutions to the system of inequalities listed below

Mathematics
1 answer:
yan [13]3 years ago
7 0

Answer:

Step-by-step explanation:

Given the simultaneous inequality

2x+y<10  ....... 1

2x-4y<8  ....... 2

Subtract both equation from each other

(2x-2x)+(y-(-4y))<10-8

0+5y<2

y < 2/5

y < 0.4

Substitute the given value of y into 1;

2x+y<10

2x + 2/5 < 10

2x < 10 - 2/5

2x < 48/5

10x < 48

x < 4.8

Hence the solution to the inequality expressions is (4.8, 0.4)

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72/80=0.9

0.9*100=9

9%
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3 years ago
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The coffee shop also sells small bag of coffee beans. the bags come in two 4/5 kilogram and 7/12 kilogram. How much more coffee
Vesnalui [34]
I believe it is 13/60

First, you would make them have common denominators
4/5 (12/12) is 48/60
7/12 (5/55 is 35/60
Second, you want to find the difference
48-35=13
So from that, I would assume that the difference between the two is 13/60
7 0
3 years ago
Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat
drek231 [11]

Answer:

E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5

We can find the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496

And we can calculate the variance with this formula:

Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246

And the deviation is:

Sd(X) = \sqrt{1.246}= 1.116

Step-by-step explanation:

For this case we have the following probability distribution given:

X          0            1        2         3        4         5

P(X)   0.031   0.156  0.313  0.313  0.156  0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

We can verify that:

\sum_{i=1}^n P(X_i) = 1

And P(X_i) \geq 0, \forall x_i

So then we have a probability distribution

We can calculate the expected value with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5

We can find the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496

And we can calculate the variance with this formula:

Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246

And the deviation is:

Sd(X) = \sqrt{1.246}= 1.116

6 0
4 years ago
Given f(x) = 2^x and g(x)=x+1, (fog)(x)=​
mixas84 [53]

Answer:

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Step-by-step explanation:

Substitute x = g(x) into f(x) , that is

(f ○ g)(x)

= f(g(x))

= f(x + 1)

= 2^{x+1}

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Please help thank you ;)
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Answer:

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