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3 years ago

DON'T GIVE ME LINK AS ANSWER PLEASE!!

Mathematics

1 answer:

iris [78.8K]3 years ago

8 0

Answer: a. The median is 5, the interquartile range is 10.

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A number cube is rolled. Find the Probability. (4 or 5)

nikklg [1K]

Answer: 2/6 or 33%

Step-by-step explanation: Hope this helps <3

6 0

2 years ago

If the surface area of the box of cereal is 272 inches squared, find the length of the box.

LekaFEV [45]

Answer:

x= 8 inches

Step-by-step explanation:

you left out the other lengths but since i had this same question once, the other lengths are 12 and 2-

dimensions of the box:

12 in x 2 in x ?

=272 square inches

and we know that there are 6 faces

area= 2 *(12 * 2) + 2 *(2*x) + 2 *(12*x)

area = 272 sq. in. = 48 + 4x + 24x

272 = 48 + 28x

272 - 48 = 28x

224 = 28x

x = 8 inches

good luck :)

i hope this helps

brainliest would be highly appreciated

have a nice day!

5 0

3 years ago

The number of lines that can be drawn perpendicular to a given line at a given point on that line in a plane is

Neko [114]

Only one.
it has a long proof.

3 0

3 years ago

Read 2 more answers

If AC=3x, AB=15, and BC=2x-1, how could we solve for x? A. Set 3x=15 B. Set 3x=2x-1 C. Set 3x+15=2x-1 D. Set 3x=15+ (2x-1) E. No

k0ka [10]

Hmm this is a very challenging question good luck finding someone who can answer it lol

5 0

3 years ago

VEEL

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago