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Harlamova29_29 [7]
3 years ago
7

Kelsey has a new baby brother! He weighs 8 lbs 3 oz. The doctor said the baby should gain about 5 ounces per week. At that rate,

how much should the baby weigh-in 3 months (12 weeks)?
Mathematics
1 answer:
yarga [219]3 years ago
5 0
Equation: 0.5x + 8.3
Plug in 12 for x and solve
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What is the equation of a line that is perpendicular to y=4x-5 and passes through (-4,6)
lozanna [386]

Answer:

y=-1/4x+5

Step-by-step explanation:

perpendicular lines have slopes that multiply to -1.

Our given line:

y=4x-5

the slope (m) in it is 4. To find the slope of the perpendicular line:

4m=-1

divide by 4

m=-1/4

the slope of the new line is -1/4

here's our equation so far:

y=-1/4x+b

Since the line will pass through the point (-4,6) we can use it to solve for b (y intercept)

so substitute (-4,6) into the equation

6=-1/4(-4)+b

6=1+b

5=b

the y intercept is 5

so our equation is:

y=-1/4x+5

hope this helps! :D

4 0
3 years ago
Simplify 3 to the 2nd Power Multiplied by 3 to the 5th Power Multiplied by 3 to the Negative 3rd Power
sweet [91]
The answer is 81.

Hope this helps.
6 0
3 years ago
HELPP ME ITS BEEN SO LONG HELP PLEASEEE HELP PLEASEE HELPP Stevie needed twine for the gifts she was wrapping for a family party
Tamiku [17]

Answer:

Your answer would be:

57.75 or 57 3/4

(I will show how many of each length of twine that is on the graph)

Point 2 1/4:

2

Point 2 3/4:

4

Point 3:

1

Point 3 1/2:

2

Point 3 3/4:

3

Point 4:

1

Point 4 1/4:

4

We can show how much length in total Stevie used with the following equation:

(2 1/4 x 2) + (2 3/4 x 4) + ( 3 x 1 ) + ( 3 1/2 x 2 ) + (3 3/4 x 3 ) + (4 x 1 ) + (4 1/4 x 4)

Each smaller equation in paraphrases shows how much of each length of twine at each point with x's on the number line. Altogether it would equal 57.75 or 57 3/4.

Step-by-step explanation:

Have a great rest of your day

#TheWizzer

3 0
2 years ago
Gina puts $ 4500 into an account earning 7.5% interest compounded continuously. How long will it take for the amount in the acco
Elza [17]

~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$5150\\ P=\textit{original amount deposited}\dotfill & \$4500\\ r=rate\to 7.5\%\to \frac{7.5}{100}\dotfill &0.075\\ t=years \end{cases}

5150=4500e^{0.075\cdot t} \implies \cfrac{5150}{4500}=e^{0.075t}\implies \cfrac{103}{90}=e^{0.075t} \\\\\\ \log_e\left( \cfrac{103}{90} \right)=\log_e(e^{0.075t})\implies \log_e\left( \cfrac{103}{90} \right)=0.075t \\\\\\ \ln\left( \cfrac{103}{90} \right)=0.075t\implies \cfrac{\ln\left( \frac{103}{90} \right)}{0.075}=t\implies\stackrel{\textit{about 1 year and 291 days}}{ 1.8\approx t}

4 0
1 year ago
Write the solution to the given inequality in interval notation.
Vikentia [17]

Answer:

The answer should be C.

7 0
3 years ago
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