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3 years ago

6

HELPPPPP PLS AND THANK YOU

1 answer:

julia-pushkina [17]3 years ago

3 0

Answer:

First, you need to know the general volume formula of a prism

$V=Sh$

We can think of the bottom as a triangle facing us, the height is 12.5ft

Use the formula to get

V=Sh=（4×6×1/2）×12.5=150 ( $ft^{3}$ )

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3x+7=8x+7<br><br> a. infinite solutions<br> b. one solution<br> c. no solution

kykrilka [37]

Answer:

The above has one solution

Hope this helps

4 0

2 years ago

Plz help me find these functions!

Iteru [2.4K]

Answer:

$\sin \alpha = \frac{5}{13}$ , $\cos \alpha = \frac{12}{13}$ , $\tan \alpha = \frac{5}{12}$ , $\cot \alpha = \frac{12}{5}$ , $\sec \alpha = \frac{13}{12}$ , $\csc \alpha = \frac{13}{5}$

Step-by-step explanation:

The angle $\alpha$ is the angle opposite to the side of length 5 and adjacent to the side of length 12. From Trigonometry we remember the following relationships:

$\sin \alpha = \frac{5}{\sqrt{5^{2}+12^{2}}}$

$\sin \alpha = \frac{5}{13}$

$\cos \alpha = \frac{12}{\sqrt{5^{2}+12^{2}}}$

$\cos \alpha = \frac{12}{13}$

$\tan \alpha = \frac{5}{12}$

$\cot \alpha = \frac{12}{5}$

$\sec \alpha = \frac{\sqrt{5^{2}+12^{2}}}{12}$

$\sec \alpha = \frac{13}{12}$

$\csc \alpha = \frac{\sqrt{5^{2}+12^{2}}}{5}$

$\csc \alpha = \frac{13}{5}$

4 0

2 years ago

13. Attend to precision. Justify each step in the solution of 5x + 15 = 0 below by stating a property

tigry1 [53]

Answer:

55/7

Step-by-step explanation:

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8 0

3 years ago

Given f(x) = x − 7 and g(x) = x2 Find F(g(4))

Thepotemich [5.8K]

Answer:

g(f): x -> 2(x-7)=2x-14 , g(f)(-1)=2*(-1)-14=-16

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Pyramid a has a lateral edge of 10 and a height of 8. Pyramid B has a lateral edges of length 15 and height 12. Both A and B are

melamori03 [73]

Answer:

Pyramid A is 10*10*8/3 which is 800/3 and Pyramid B is 15*15*12/3 which is 2700/3, so the ratio would simply be 8:27 uwu

Step-by-step explanation:

3 0

2 years ago