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Answer:
(x +6)^2 +(y -10)^2 = 225
Step-by-step explanation:
The standard form equation for a circle is ...
(x -h)^2 + (y -k)^2 = r^2
where the center is (h, k) and the radius is r.
The center of a circle is the midpoint of any diameter. The midpoint between two points is the average of their coordinates.
((-15, -2) +(3, 22))/2 = (-15+3, -2+22)/2 = (-6, 10)
The radius can be found using the distance formula, or by simply putting one of the given points in the equation for the circle to see what the constant (r^2) needs to be.
(x -(-6))^2 +(y -10)^2 = (-15-(-6))^2 +(-2-10)^2
(x +6)^2 +(y -10)^2 = 81 +144 = 225
The equation of the circle is ...
(x +6)^2 +(y -10)^2 = 225
Answer:
It can be concluded that the intersection of a chord and the radius that bisects it is at right angle. The two are perpendicular.
Step-by-step explanation:
i. Construct the required circle of any radius as given in the question, then locate the chord. A chord joins two points on the circumference of a circle, but not passing through its center.
ii. Construct the radius to bisect the chord, dividing it into two equal parts.
Then it would be observed that the intersection of a chord and the radius that bisects it is at right angle. Thus, the chord and radius are are perpendicular to each other.
The construction to the question is herewith attached to this answer for more clarifications.
Answer:
2 hours
Step-by-step explanation:
if you can type 1 1/3 pages every 15 minutes than you can type 5 1/3 pages every hour. you divide 10 2/3 pages by how many pages Lee can type every hour and the result is 2 hours
<span>"For which value of k does the system have no real number solutions?"
The answer is 4, because 4+4</span>≠16.
<span>
"For which value of k does the system have one real number solution?"
</span>The answer is -0.25, because the linear line because tangent with the parent function.
<span>"For which value of k does the system have two real number solutions?"
</span>The answer is 2, because the linear function intercepts the parent function 2 times.
- i hope these are the answers you are looking for.