First one was divided by 2 second was divided by 4 so now you do 16/8 which gives you two then you do 2/16 which is 1/8 so the next two answers are 2 and 1/8

5 0

3 years ago

Please help me for the brainliest answer

7nadin3 [17]

The answer is 928cm. There are 5 sides. When you find the area of a triangle you multiply base times height then divide by two. But in this case there are two identical triangles so you don’t need to divide. 24x12=288. Then you find the area of the long sides. Multiple 25 and 10 and you get 250. There are two of those sides. Now the last thing to do is find the area of the bottom side. For that one you multiply 14 and 10 and get 140. Now you add all of that together and get 928cm.

4 0

4 years ago

The quotient of j and 8 expressed

Oksana_A [137]

$j:8=\dfrac{j}{8}$

8 0

3 years ago

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

7 0

3 years ago