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nata0808 [166]
2 years ago
6

A line passes through A(6,5) and B(4,2) find equation of a line parallel to AB and passes through (7,10)

Mathematics
1 answer:
olga55 [171]2 years ago
6 0

Answer:

2y = 3x-1

Step-by-step explanation:

We start by calculating the slope of AB

m = (y2-y1)/(x2-x1) = (2-5)/(4-6) = 3/2

Since the two lines are parallel, then their slopes are equal

We use the point-slope form to get the equation

That will be;

y-y1 = m(x-x1)

y-10 = 3/2(x-7)

y = 3x/2-21/2+ 10

Multiply through by 2

2y= 3x -21 + 20

2y = 3x-1

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3.602 × 10 − 4 thx luvs
lorasvet [3.4K]

♡ The Question ♡

- 3.602 × 10 − 4

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ The Answer ♡

- 32.02

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ The Explanation/Step-By-Step ♡

- 3.602 x 10 - 4

Multiply the numbers: 3.602 x 10 = 36.02

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Subtract the numbers: 36.02 - 4 = 32.02!

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arlik [135]

Answer:

\frac{\sqrt{17} }{7}

Step-by-step explanation:

Using the Pythagorean identity

sin²x + cos²x = 1, then

sinx = \sqrt{1-cos^2x}

Note that (\frac{4\sqrt{2} }{7})² = \frac{32}{49}

sinΘ = \sqrt{1-(32/49)}

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