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mash [69]
3 years ago
13

Write a program that will ask the user for three different numerical values. The program should then decide whether the values a

re equally spaced. C++
Computers and Technology
1 answer:
tino4ka555 [31]3 years ago
8 0

Answer:

See the code in the Eplanation

Explanation:

// Online C++ compiler to run C++ program online

#include <iostream>

using namespace std;

int main() {

  int firstNumber;

  int secondNumber;

  int thirdNumber;

 

 

cout<< "Enter the firstNumber: ";

cin >> firstNumber;

cout << "Enter the secondNumer: ";

cin >> secondNumber;

cout << "Enter the thirdNumber: ";

cin >> thirdNumber;

int upperbound= abs(firstNumber-secondNumber);

int lowerbound= abs(secondNumber-thirdNumber);

if (lowerbound==upperbound){

cout << "The Three Numbers are Equally spaced";

   

}

  else{

      cout << "The Three Numbers are NOT Equally spaced";

}

}

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Answer:

See explaination

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#include <fstream>

#include <iostream>

#include <iomanip>

using namespace std;

int main()

{

// Fill in the code to define payfile as an input file

ifstream payfile;

float gross;

float net;

float hours;

float payRate;

float stateTax;

float fedTax;

cout << fixed << setprecision(2) << showpoint;

// Fill in the code to open payfile and attach it to the physical file

// named payroll.dat

payfile.open("payroll.dat");

// Fill in code to write a conditional statement to check if payfile

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cout << "Error opening file. \n";

cout << "It may not exist where indicated" << endl;

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}

ofstream outfile("pay.out");

cout << "Payrate Hours Gross Pay Net Pay"

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// Fill in code to prime the read for the payfile file.

payfile >> hours;

// Fill in code to write a loop condition to run while payfile has more

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while(!payfile.eof())

{

payfile >> payRate >> stateTax >> fedTax;

gross = payRate * hours;

net = gross - (gross * stateTax) - (gross * fedTax);

cout << payRate << setw(15) << hours << setw(12) << gross

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outfile << payRate << setw(15) << hours << setw(12) << gross

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}

payfile.close();

outfile.close();

return 0;

}

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