12 laps because Lee ran 3 and that's half of what ray ran so times that by 2 and then times 6 by 2 and that's your answer
Answer:
k=2
Problem:
if the equation x^2 +(k+2)x+2k=0 has equal roots,then the value of k is ..
Step-by-step explanation:
Since the coefficient of x^2 is 1, we can use this identity to aid us: x^2+bx+(b/2)^2=(x+b/2)^2.
So we want the following:
[(k+2)/2]^2=2k
Apply the power on the left:
(k+2)^2/4=2k
Multiply both sides by 4:
(k+2)^2=8k
Expand left side:
k^2+4k+4=8k *I used identity (x+c)^2=x^2+2xc+c^2
Subtract 8k on both sides:
k^2-4k+4=0
Factor using the identity mentioned a couple lines above:
(k-2)^2=0
Since zero squared is zero, we want k-2=0.
Adding both sides by 2 gives k=2.
Answer:
c=2.4a+2537.8
a=-2.5/6c+1057.4
Step-by-step explanation:
solve for c:
2.50c+6a=6344.50
-6a -6a
2.50c=-6a+6344.50
/2.50 /2.50 /2.50
c=2.4a+2537.8
solve for a:
2.50c+6a=6344.50
-2.5c -2.5c
6a=-2.5c+6344.50
/6 /6 /6
a=-2.5/6c+1057.4
The answer is 4 1/3. Would you like an explanation?
9514 1404 393
Answer:
cot(θ) = 4/5
Step-by-step explanation:
In the polar/rectangular coordinate representation (x, y) ⇔ (r; θ), we know that ...
(x, y) = (r·cos(θ), r·sin(θ))
From the various trig definitions and identities, we also know that ...
cot(θ) = cos(θ)/sin(θ) = (x/r)/(y/r) = x/y
For the given (x, y) = (-4, -5), the cotangent is ...
cot(θ) = -4/-5 = 4/5
