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kobusy [5.1K]
3 years ago
13

Simultaneous Equation

Mathematics
2 answers:
cupoosta [38]3 years ago
8 0

I will solve your system by substitution.

(You can also solve this system by elimination.)

2x+y=13;5x−4y=13

Step 1: Solve 2x+y=13 for y:

Solve 2x + y = 13 for y

2x + y + -2x = 13 + -2x

(add -2x to both sides)

y = -2x + 13

Step 2: Substitute −2x+13 for y in 5x−4y=13:

5x−4y=13

5x−4(−2x+13)=13

13x−52=13(Simplify both sides of the equation)

13x−52+52=13+52(Add 52 to both sides)

13x=65

(Divide both sides by 13)

13x/13 = 65/13

x = 5

Step 3: Substitute 5 for x in y = −2x+13:

y = −2x+13

y = (−2)(5)+13

(Simplify both sides of the equation)

y = 3

Answer: x= 5, y= 3

makkiz [27]3 years ago
7 0

Answer:

x = 5 ,

y = 3

Use substitution method .

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3 years ago
HELP NEEDED!
Ilia_Sergeevich [38]

Answer:

x = 12.6

Step-by-step explanation:

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By substituting these measures in teh expression,

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3 years ago
HELP GEOMETRY PLEASE
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So, for the first problem, we have 94 \cdot 2 = x+103, so x = 188 - 103 = 85. 

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For the last problem, 106 \cdot 2 = x + 88, so x = 212 - 88 = 124.

Feel free to comment below if you have any questions!
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3 years ago
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