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3 years ago

Simultaneous Equation

Mathematics

2 answers:

cupoosta [38]3 years ago

8 0

I will solve your system by substitution.

(You can also solve this system by elimination.)

2x+y=13;5x−4y=13

Step 1: Solve 2x+y=13 for y:

Solve 2x + y = 13 for y

2x + y + -2x = 13 + -2x

(add -2x to both sides)

y = -2x + 13

Step 2: Substitute −2x+13 for y in 5x−4y=13:

5x−4y=13

5x−4(−2x+13)=13

13x−52=13(Simplify both sides of the equation)

13x−52+52=13+52(Add 52 to both sides)

13x=65

(Divide both sides by 13)

13x/13 = 65/13

x = 5

Step 3: Substitute 5 for x in y = −2x+13:

y = −2x+13

y = (−2)(5)+13

(Simplify both sides of the equation)

y = 3

Answer: x= 5, y= 3

makkiz [27]3 years ago

7 0

Answer:

x = 5 ,

y = 3

Use substitution method .

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Use the method of cylindrical shells to find the volume generated by rotating the region bounded by the given curves about the s

Furkat [3]

Answer:

$\frac{16\pi}{3}$ .

Step-by-step explanation:

I graphed the region in the image below. The blue line is y=3, the purple line is x=1 and the green curve is y = $4x-x^{2}$ . The shaded region in blue is the region we are going to rotate.

Now, to find the volume v= $2\pi \int\limits^a_b {p(x)h(x)} \, dx$ where a=1, b=3 (left and right points of the region), p(x) is the distance from the rotation axis to the diferential Δx, we say p(x)=x and h(x) is the height of the region, in this case is h(x)= $4x-x^{2}-3$ . Then,