I will solve your system by substitution.
(You can also solve this system by elimination.)
2x+y=13;5x−4y=13
Step 1: Solve 2x+y=13 for y:
Solve 2x + y = 13 for y
2x + y + -2x = 13 + -2x
(add -2x to both sides)
y = -2x + 13
Step 2: Substitute −2x+13 for y in 5x−4y=13:
5x−4y=13
5x−4(−2x+13)=13
13x−52=13(Simplify both sides of the equation)
13x−52+52=13+52(Add 52 to both sides)
13x=65
(Divide both sides by 13)
13x/13 = 65/13
x = 5
Step 3: Substitute 5 for x in y = −2x+13:
y = −2x+13
y = (−2)(5)+13
(Simplify both sides of the equation)
y = 3
Answer: x= 5, y= 3
