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2 years ago

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Jeff wants to save $4000 to buy a used car. He has already saved $850. He plans to save an additional $150 each week. write and

solve an equation to represent the number of weeks remaining w until he can afford the car.

1 answer:

kupik [55]2 years ago

8 0

Answer:

21 weeks

Step-by-step explanation:

150*21=3150

3150+850=4000

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Changing the equation into slope form: $y = mx + c$ , where $m$ is the slope [gradient] and $c$ is the y-intercept.

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Graphing $y=- \frac{2}{3}x+490$ using slope-intercept method:
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The graph of this function is shown below. The intercepts are labelled at:
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x = 735

-----------------------------------------------------------------------------------------------------------

Next month's profit equation

$2x+3y=1593$

Rewriting this into slope-equation form

$3y = -2x+1593$
$y=- \frac{2}{3}+ \frac{1593}{3}$
$y= - \frac{2}{3}+531$

The gradient, $m$ , equals to $- \frac{2}{3}$
The y-intercept, $c$ , equals to 531

The equation still has the same gradient with last month's profit equation but different y-intercept.

-------------------------------------------------------------------------------------------------------------

A linear graph show points of (0, 300) and (450, 0)

We work out the slope:
$\frac{300-0}{0-450} = \frac{300}{-450}=- \frac{20}{30} =- \frac{2}{3}$

Y-intercept at x = 0, so it's at y = 300

Equation $y = - \frac{2}{3}+300$

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