Answer:
c = 4.79 feet
Step-by-step explanation:
Given question is incomplete without a picture; find the question with the attachment.
Two poles AD and DB of same length are leaning against each other.
Distance between the poles (AB) = 45 feet
m(∠ADB) = 180°- (60 + 50)°
= 70°
By sine rule,


= 36.68 ft
Similarly,
DB = 
= 41.47 ft
Now c = DB - AD
= 41.47 - 36.68
= 4.79 feet
Answer:
= 8
= 6
Therefore the co-ordinate of the center of mass is = 
Step-by-step explanation:
Center of mass: Center of mass of an object is a point on the object. Center of mass is the average position of the system.
Center of mass of a triangle is the centriod of a triangle.
Given that m₁= 4, m₂=3, m₃=3 and the points are P₁(2,-3), P₂(-3,1) and P₃(3,5)
= ∑(mass × x-co-ordinate)
= ∑(mass × y-co-ordinate)
Therefore
= (4×2)+{3×(-3)}+(3×3)
=8
= {4×(-3)}+{3×1}+(3×5)
=6
The x co-ordinate of the center of mass is the ratio of
to the total mass.
The y co-ordinate of the center of mass is the ratio of
to the total mass.
Total mass (m) = m₁+ m₂+ m₃
= 4+3+3
=10
The x co-ordinate of the center of mass is 
The y co-ordinate of the center of mass is 
Therefore the co-ordinate of the center of mass is = 
Answer:
-6(2b-c-3)
Step-by-step explanation:
Collect like terms
-12b+6c+12+6
Add the 2 numbers on right
-12b+6c+18
Factor -6 out of expression
-6(2b-c-3)
Answer:
Step-by-step explanation:
what is the problems ?
Hello!
Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.
Horizontal asymptotes are determined by:
1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.
2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.
3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.
To find the vertical asymptote:
2x² - 10 = 0
2(x² - 5) = 0
(x - √5)(x + √5) = 0
x = √5 and x = -√5
Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.
To find the horizontal asymptote:
If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.
Therefore, the horizontal asymptote of this function is y = 0.
Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0