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inysia [295]
3 years ago
15

Factor 5x^2+20x+12​

Mathematics
1 answer:
Readme [11.4K]3 years ago
6 0

Answer:

5 x ^2  +  20 x  +  12

Step-by-step explanation:

not factorable

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After a storm, two street lights with the same length are leaning against each
Ray Of Light [21]

Answer:

c = 4.79 feet

Step-by-step explanation:

Given question is incomplete without a picture; find the question with the attachment.

Two poles AD and DB of same length are leaning against each other.

Distance between the poles (AB) = 45 feet

m(∠ADB) = 180°- (60 + 50)°

               = 70°

By sine rule,

\frac{sin50}{AD}=\frac{sin70}{45}=\frac{sin60}{DB}

AD=\frac{45\times (sin50)}{sin70}

      = 36.68 ft

Similarly,

DB = \frac{45\times sin60}{sin70}

     = 41.47 ft

Now c = DB - AD

           = 41.47 - 36.68

           = 4.79 feet

4 0
3 years ago
The masses mi are located at the points Pi. Find the moments Mx and My and the center of mass of the system. m1 = 4, m2 = 3, m3
viva [34]

Answer:

M_x= 8

M_y = 6

Therefore the co-ordinate of the center of mass is = (\frac{4}{5},\frac{3}{5})

Step-by-step explanation:

Center of mass: Center of mass of an object is a point on the object. Center of mass is the average position of the system.

Center of mass of a triangle is the centriod of a triangle.

Given that m₁= 4, m₂=3, m₃=3 and the points are P₁(2,-3), P₂(-3,1) and P₃(3,5)

M_x = ∑(mass × x-co-ordinate)

M_y = ∑(mass × y-co-ordinate)

Therefore  

M_x = (4×2)+{3×(-3)}+(3×3)

     =8

M_y = {4×(-3)}+{3×1}+(3×5)

    =6

The x co-ordinate of the center of mass is the ratio of M_x to the total mass.

The y co-ordinate of the center of mass is the ratio of M_y to the total mass.

Total mass (m) = m₁+ m₂+ m₃

                        = 4+3+3

                        =10

The x co-ordinate of the center of mass is \frac {8}{10} = \frac {4}{5}

The y co-ordinate of the center of mass is \frac{6}{10}=\frac{3}{5}

Therefore the co-ordinate of the center of mass is = (\frac{4}{5},\frac{3}{5})

4 0
3 years ago
Simplify the expression -4b+8c+12-8b-2c+6
Veseljchak [2.6K]

Answer:

-6(2b-c-3)

Step-by-step explanation:

Collect like terms

-12b+6c+12+6

Add the 2 numbers on right

-12b+6c+18

Factor -6 out of expression

-6(2b-c-3)

8 0
3 years ago
I need help to solve a iniqualities
Natasha_Volkova [10]

Answer:

Step-by-step explanation:

what is the problems ?

7 0
3 years ago
Read 2 more answers
Find the vertical and horizontal asymptote if they exist
tresset_1 [31]

Hello!

Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.

Horizontal asymptotes are determined by:

1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.

3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.

To find the vertical asymptote:

2x² - 10 = 0

2(x² - 5) = 0

(x - √5)(x + √5) = 0

x = √5 and x = -√5

Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.

To find the horizontal asymptote:

If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

Therefore, the horizontal asymptote of this function is y = 0.

Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0

7 0
3 years ago
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