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postnew [5]
3 years ago
7

If f(y) = 2y - 2/5, what is f(f^-1(1024))?

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
7 0

Answer:

-0.399

Step-by-step explanation:

f^-1(1024)=(2*1024-2/5)^-1= 0.000488

f(0.000488)=2*0.000488-2/5= -0.399

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Rabbit population can double every 30 days, if there are 20 rabbits on a farm, how many rabbits will be on the farm after 210 da
Art [367]

Knowing the amount doubles every 30 days, we'll have to find how many times it'lll double in the 210-day time frame:

210 / 30 = 7


It doubles 7 times. If we were to write a rough, not worked on expresion representing that, knowing the starting population was of 20, we would write:

(((((((20 * 2) * 2) * 2) * 2) * 2) * 2) * 2) = 2560 rabbits




Hope it helped,



Happy homework/ study exam!




7 0
3 years ago
Read 2 more answers
Hey there people Im doing a poll
quester [9]
My favorite is probably aweSAMdude
5 0
3 years ago
2 If m please help me
Nadusha1986 [10]

Answer:

x = 18

m∠HCB = 36

Step-by-step explanation:

The measure of angle FBC is 8x and the measure of angle HCB is 2x. If you add the measures of both angles it will equal to 180 degrees. This can be represented in an equation:

8x + 2x = 180

10x = 180

Divide both sides of the equation by 10 to isolate the x:

10x/10 = 180/10

x = 18

Now that we know the value of x, we can find the measure of angle HCB:

2x

2(18)

36

The measure of angle HCB is 36.

I hope this helps :)

8 0
3 years ago
BRAINLIEST IF CORRECT PLEASE USE WORK!
ladessa [460]

Answer:


To find the x-intercept, substitute in  0  for  y  and solve for  x . To find the y-intercept, substitute in  0  for  x  and solve for  y .

x-intercept: (− 45 , 0 )

y-intercept:  ( 0 , − 15 )

7 0
3 years ago
Read 2 more answers
A random variable X follows the uniform distribution with a lower limit of 670 and an upper limit of 750.a. Calculate the mean a
DENIUS [597]

You can compute both the mean and second moment directly using the density function; in this case, it's

f_X(x)=\begin{cases}\frac1{750-670}=\frac1{80}&\text{for }670\le x\le750\\0&\text{otherwise}\end{cases}

Then the mean (first moment) is

E[X]=\displaystyle\int_{-\infty}^\infty x\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x\,\mathrm dx=710

and the second moment is

E[X^2]=\displaystyle\int_{-\infty}^\infty x^2\,f_X(x)\,\mathrm dx=\frac1{80}\int_{670}^{750}x^2\,\mathrm dx=\frac{1,513,900}3

The second moment is useful in finding the variance, which is given by

V[X]=E[(X-E[X])^2]=E[X^2]-E[X]^2=\dfrac{1,513,900}3-710^2=\dfrac{1600}3

You get the standard deviation by taking the square root of the variance, and so

\sqrt{V[X]}=\sqrt{\dfrac{1600}3}\approx23.09

8 0
3 years ago
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