Answer:
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Therefore the length of a side of a cube is ![\sqrt[3]{64}\ or\ 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%5C%20or%5C%204)
</h2>
Step-by-step explanation:
The volume of a cube is expressed as L³ where L is the length of each side of the cube.
Given volume of a cube = 64in³
On substituting;
64 = L³
Taking the cube root of both sides to determine L we have;
![\sqrt[3]{64} = (\sqrt[3]{L})^{3}\\\sqrt[3]{64} = L\\L=4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%3D%20%28%5Csqrt%5B3%5D%7BL%7D%29%5E%7B3%7D%5C%5C%5Csqrt%5B3%5D%7B64%7D%20%3D%20L%5C%5CL%3D4)
Therefore the length of a side of a cube is
First, rearrange the equation so that it is solving for y:
3x - y = 1
+y +y
3x = y + 1
-1 -1
3x - 1 = y
Now substitute the domain values you have listed into the 'x' of the equation to get the values for y.
For example:
3(-3) - 1 = y
-9 - 1 = y
y = -10
Answer:
x = 19
Step-by-step explanation:
The two angles with measures are supplementary.
6x + 9 + 4x - 19 = 180
10x - 10 = 180
10x = 190
x = 19
The answer should not depend on which machine or which pencil you use to
find it. If you work a problem two different ways and get two different answers,
then at least one of them is wrong, and there's a pretty good chance that both
of them are.
(9.99 of anything) + (1.11 of the same thing) = 11.1 of them
9.99 (x 10^-2) + 1.11 (x 10^-2) = <em>11.1 (x 10^-2)</em> .
Can we do any more with that ?
10^-2 = 1 / 10^2 = 1 / 100 .
11.1 x 10^-2 = 11.1 / 100 = <em>0.111</em>
Hello,
y+1/2=3(x-2)
or y=3x-13/2
