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attashe74 [19]
2 years ago
8

What is 6/5 of 7003= PLEASE HELP AGAIIIN!!!!!!!!!

Mathematics
1 answer:
ikadub [295]2 years ago
4 0

Answer:

8,403.6

Step-by-step explanation:

6/5 of 7003

= 6/5 × 7003

= 42,018/5

= 8,403.6

Hence 6/5 of 7003 is 8,403.6

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If the goal of this question is to solve for x than the correct answer is 20. Hope this helped.
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689x+47x-89 dose anyone know how to solve this?
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Answer:

736x-89

Step-by-step explanation:

i think all you can do here is add the numbers that have an X in them so adding 689x+47x=736x and you leave the 89 so it becomes 736x-89

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PLEASE HELP QUICKLY I WILL MARK BRAINLIEST AND IF YOU ARE TRYING TO GET FREE POINT I WILL REPORT YOU
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Hi could you please help? Write 2.96 as a mixed number or fraction in simplest form. My family is trying to help me but we're ba
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A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular
Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = \frac{360}{8}

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

sin 22.5=\frac{AC}{OA}

=\frac{AC}{x}

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, cos 22.5=\frac{OC}{OA}

=\frac{OC}{x}

So, OC = x cos 22.5°.

Area of Δ AOB = \frac{1}{2}(AB)(OC)

= \frac{1}{2} × (2x sin 22.5°) × (x cos 22.5°)

= \frac{1}{2} x^{2} (2 sin 22.5° cos 22.5°)

= \frac{1}{2} x^{2} sin 45°

= x^{2} / 2\sqrt{2}

Area of the octagonal gazebo = 8 × one triangular area

= 8 × (x^{2} / 2\sqrt{2})

=2\sqrt{2} x^{2}

=2.828x^{2}

Area required for mulch = circular area - area of the gazebo

=3.14x^{2} -2.828x^{2}

=0.312x^{2}

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = 0.312x^{2} × 1.5

=0.468x^{2}

Hence, total cost g(m) = 0.468x^{2}.

4 0
3 years ago
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