Simplify:
−3=12y−5(2y−7)
−3=12y+(−5)(2y)+(−5)(−7)(Distribute)
−3=12y+−10y+35
−3=(12y+−10y)+(35)(Combine Like Terms)
−3=2y+35
Flip the equation.
2y+35=−3
Subtract 35 from both sides.
2y+35−35=−3−35
2y=−38
Divide both sides by 2.
2y/2=−38/2
y=−19
Answer:
X = 11
X = 7
Step-by-step explanation:
Part 1:
The measure of an inscribed angle is half the measure of an intercepted arc. So 1/2 mCE = m∠CDE
158 ÷ 2 = 79
You need to find x so you're going to set your equation of (8x - 9) = 79
Then you're going to add 9 to both sides to get 8x = 88
Divide both sides by 8 to get x = 11
Part 2:
We know that WY is 180 because it's a semicircle. Using this and the knowledge that ∠WXY is half the measure of the intercepted arc (180), we know that our equation should be (13x - 1) = 90
add 1 to both sides and our equation is (13x = 91)
Divide both sides by 13 and...
x = 7
Distribute -2(x - 3)
4x - 2x + 6 = 10 + -9
Simplify
2x = -5
x = -2.5
Answer:
A, C
Step-by-step explanation:
Answer:
Step-by-step explanation:
Suppose at t = 0 the person is 1m above the ground and going up
Knowing that the wheel completes 1 revolution every 20s and 1 revolution = 2π rad in angle, we can calculate the angular speed
2π / 20 = 0.1π rad/s
The height above ground would be the sum of the vertical distance from the ground to the bottom of the wheel and the vertical distance from the bottom of the wheel to the person, which is the wheel radius subtracted by the vertical distance of the person to the center of the wheel.
(1)
where 
is vertical distance from the ground to the bottom of the wheel, 
is the vertical distance from the bottom of the wheel to the person, R = 10 is the wheel radius, 
is the vertical distance of the person to the center of the wheel.
So solve for in term of t, we just need to find the cosine of angle θ it has swept after time t and multiply it with R
Note that is negative when angle θ gets between π/2 (90 degrees) and 3π/2 (270 degrees) but that is expected since it would mean adding the vertical distance to the wheel radius.
Therefore, if we plug this into equation (1) then
