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RoseWind [281]
3 years ago
5

Solve the system of equations by substitution: y=4x-10 y=x+2

Mathematics
2 answers:
finlep [7]3 years ago
8 0

Answer:

(4, 6)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

y = 4x - 10

y = x + 2

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                           4x - 10 = x + 2
  2. Subtract <em>x</em> on both sides:          3x - 10 = 2
  3. Add 10 on both sides:                3x = 12
  4. Divide 3 on both sides:             x = 4

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define equation:                     y = x + 2
  2. Substitute in <em>x</em>:                        y = 4 + 2
  3. Add:                                         y = 6

viktelen [127]3 years ago
5 0
Plug in x + 2 for y
x + 2 = 4x - 10
Subtract x
2 = 3x - 10
Add 10, 12 = 3x, x = 4
Plug into second equation
y = 4 + 2, y = 6
Solution: x = 4, y = 6... or (4,6)
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Resposta:

Primer rectangle:

Amplada = 11

Longitud = 14

Segon rectangle:

Amplada = 12

Longitud = 15

Tercer rectangle:

Amplada = 13

Longitud = 16

Explicació pas a pas:

Donat que:

Primer rectangle:

Amplada = x

Longitud = x + 3

2n rectangle:

Augment de la dimensió d'1 cm respecte al primer rectangle;

Amplada = x + 1

Longitud = x + 4

3r rectangle:

Augment de la dimensió de 2 cm respecte al primer rectangle;

Amplada = x + 2

Longitud = x + 5

Suma dels tres perímetres del rectangle:

Perímetre d'un rectangle: 2 (l + O)

Primer rectangle:

2 (x + x + 3) = 2 (2x + 3) = 4x + 6

2n:

2 (x + 1 + x + 4) = 2 (2x + 5) = 4x + 10

3r:

2 (x + 2 + x + 5) = 2 (2x + 7) = 4x + 14

Suma de perímetres = 162

(4x + 6 + 4x + 10 + 4x + 14) = 162

12x + 30 = 162

12x = 162 - 30

12x = 130

x = 11

Per tant,

Primer rectangle:

Amplada = 11

Longitud = 11 + 3 = 14

2n rectangle:

Amplada = 11 + 1 = 12

Longitud = 11 + 4 = 15

3r rectangle:

Amplada = 11 + 2 = 13

Longitud = 11 + 5 = 16

8 0
3 years ago
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