I guess the function is . Then
and
.
The derivative is , but there is no
such that
This doesn't contradict Rolle's theorem because does not exists. In other words,
is not differentiable on (-27, 27), so the conditions of Rolle's theorem are not met. (Looks like that would be the last option, or the second to last option if the last one is "Nothing can be concluded")
Answer:
The points which satisfy the given lines is ( 1 , 1 )
Step-by-step explanation:
Given as :
The equation of lines is
y = 3 x - 2 ........ 1 And
y = - 2 x + 3 ........ 2
From equation given
3 x - 2 = - 2 x + 3
Or , 3 x + 2 x = 3 +2
Or, 5 x = 5
So , x = = 1
Put the value of x in eq 1
So, y = 3 ( 1 ) - 2
Or, y = 3 - 2 = 1
∴, the points ( x , y ) = ( 1 , 1 )
Hence The points which satisfy the given lines is ( 1 , 1 ) Answer
Answer: proof below
<u>Step-by-step explanation:</u>
Use the Difference formula for sin:
sin (A - B) = sin(A)·cos(B) - cos(A)·sin(B)
sin (180° - θ) = sin(180°)·cos(θ) - cos(180°)·sin(θ)
= 0 · cos(θ) - -1 · sin(θ)
= 0 - -sin(θ)
= + sin(θ)
sin (180° - θ) = sin(θ)