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nasty-shy [4]
4 years ago
12

Solve y=1/4x-1 if the domain is {-4,-2,0,2,4}.

Mathematics
1 answer:
kipiarov [429]4 years ago
5 0

Allowed values for y: -2,-\frac{3}{2},-1,-\frac{1}{2},0

Step-by-step explanation:

The domain of a function f(x) represents the set of values for which the function is defined. In other words, it represents the values of x that are allowed.

The function in this problem is:

y=\frac{1}{4}x-1

And the domain is

D: {-4,-2,0,2,4}

This means that these are the only allowed values for x. We can find the range of the functions (the possible values for y) simply by substituting these values of x into the function. We get:

For x = -4,

y=\frac{1}{4}(-4)-1=-1-1=-2

For x = -2,

y=\frac{1}{4}(-2)-1=-\frac{1}{2}-1=-\frac{3}{2}

For x = 0,

y=\frac{1}{4}(0)-1=-1

For x = 2,

y=\frac{1}{4}(2)-1=\frac{1}{2}-1=-\frac{1}{2}

For x = 4,

y=\frac{1}{4}(4)-1=1-1=0

Therefore, the allowed values for y are:

-2,-\frac{3}{2},-1,-\frac{1}{2},0

Learn more about domain and range:

brainly.com/question/7128279

brainly.com/question/9607945

brainly.com/question/1485338

#LearnwithBrainly

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A toy rocket launched into the air has a height ( h feet) at given time ( t seconds) as h= -16^2+160t until it hits the ground.
Gennadij [26K]

Answer:

t = \frac{53}{32}

Step-by-step explanation:

h=\:-16^2+160t

9=\:-16^2+160t      substitute

-16^2+160t=9

-256+160t=9

-256+160t+256=9+256

160t=265

\frac{160t}{160}=\frac{265}{160}

t=\frac{53}{32}

At  \frac{53}{32}  seconds it is at a height of 9 ft.

4 0
3 years ago
Find the inverse laplace transform of: (2 s + 4) / (s - 3)^3
Serhud [2]

Answer:

e^{3t}(2t+5t^{2})

Step-by-step explanation:

L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=

Using the Translation theorem to transform the s-3 to s, that means multiplying by and change s to s+3

Translation theorem:L^{1} [F(s-a)=L^{-1}[F(s)|_{s \to s-a}\\ L^{1} [F(s-a)=e^{at} f(t)

L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=e^{3t} L^{-1}[\frac{2(s+3)+4}{s^{3}} ]

Separate the fraction in a sum:

e^{3t} L^{-1}[\frac{2s+10}{s^{3}} ]=e^{3t} L^{-1}[\frac{2s}{s^{3}}+\frac{10}{s^{3}} ]=e^{3t} (L^{-1}[\frac{2}{s^{2}}]+ L^{-1}[\frac{10}{s^{3}}])

The formula for this is:

L^{-1}[\frac{n!}{s^{n+1}} ]=t^{n}

Modify the expression to match the formula.

e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ \frac{10}{2} L^{-1}[\frac{2}{s^{2+1}}])=e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])

Solve

e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])=e^{3t}(2t+5t^{2} )

6 0
3 years ago
What is the diameter of a circular swimming pool with a radius of 8 feet?
Alenkasestr [34]
We know that,

diameter is twice the radius, I.e d = 2r

Now d = 2(8)ft = 16 feet
5 0
3 years ago
Help ME PLEASE
amm1812
Did you ever answer it??? I am stuck on this one and I don't know how to figure it out so I can get the answer myself.

8 0
4 years ago
What is the ratio of nv/n (1357 k) and nv/n (298k)?
NeX [460]
Ratio is a way of comparing two numbers which are of the same kind. It is normally expressed by separating two numbers with a colon(:) or you could also use division sign (/). The only way that ratios can have mean is that both number should be non-zeros and both of them should have the same sign. Thus having this in mind, the ratio of the numbers above will be:
(1357k)/(298k)
=1357:298

6 0
4 years ago
Read 2 more answers
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