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ANEK [815]
3 years ago
14

¿Buenos días cómo estás?

Mathematics
2 answers:
kodGreya [7K]3 years ago
5 0

Answer:

spanish:estoy bien

Step-by-step explanation:

english:I am good

Montano1993 [528]3 years ago
3 0

Answer:

very tired :(

Step-by-step explanation:

You might be interested in
Need help please!
Paul [167]

Answer:

a=\frac{m}{(q+r^2)}

Step-by-step explanation:

We begin with the equation qa+r^2a=m for which we need to solve for a.

The first thing that we can do is to factor out the a from both terms on the left side of the equation

qa+r^2a=m\\\\a(q+r^2)=m

Then we can divide each side by (q+r^2) to isolate a

a(q+r^2)=m\\\\a=\frac{m}{(q+r^2)}

8 0
3 years ago
Suppose the foot of a 12-foot ladder was placed 4 feet from a building how high up on the building would the top of the ladder r
NikAS [45]

Use the pythagorean theorem.

The foot of the ladder is 4 feet away from the building (leg 1)

The height of the building is leg 2

The ladder, which would be at an angle, is 12 feet. So our hypotenuse would be 12. The equation for this would be a²+4²=12²

We can then begin to solve

a² + 16 = 144  

a² = 128

a=11.31

So, our answer is: The top of the ladder reaches the building at 11.31 feet up

4 0
3 years ago
What is the expanded form of the series represented below?
34kurt
I think the answer is B
4 0
3 years ago
Roger sees water balloons fall past his window. He notices that each balloon strikes the sidewalk 1.01 s after passing his windo
vodomira [7]

Part A The balloon is travelling at 19.8 m/s when it passes Roger's window

Part B The balloon was released from the 7th floor.

To solve the questions, we need to use the equations of motion

<h3>What are equations of motion?</h3>

Equations of motion are equations used to solve for the motion of an object under a constant acceleration

<h3>Part A How fast are the balloons traveling when they pass Roger's window?</h3>

Since Roger sees water balloons fall past his window and he notices that each balloon strikes the sidewalk 1.01 s after passing his window. Roger's room is on the third floor, 15 m above the sidewalk.

Using the equation of motion s = ut - 1/2gt² where

  • s = height of Roger's room above sidewalk = 15 m,
  • u = speed of balloon at Roger's window,
  • t = time it takes balloon to reach sidewalk = 1.01 s and
  • g = acceleration due to gravity = 9.8 m/s²

Making u subject of the formula, we have

u = s/t + 1/2gt

Substiting the values of the variables into th equation, we have

u = s/t + 1/2gt

u = 15 m/1.01 s + 1/2 × 9.8 m/s² × 1.01 s

u = 14.851 m/s + 1/2 × 9.898 m/s

u = 14.851 m/s + 4.949 m/s

u = 19.8 m/s

So, the balloon is travelling at a speed of 19.8 m/s when it passes Roger's window

<h3>Part B From what floor are they being released</h3>

Since the balloons are released from rest, they have zero velocity.

So, using the equation of motion

v² = u² - 2gh where

  • u = initial velocity of balloon = 0 m/s (since it is released from rest),
  • v = speed of balloon at Roger's window = 19.8 m/s,
  • g = acceleration due to gravity = 9.8 m/s² and
  • h = height which balloon was released

Making h subject of the formula, we have

h = (v² - u²)/2g

Substituting the values of the variables into ther equation,we have

h = (v² - u²)/2g

h = [(19.8 m/s)² - (0 m/s²)]/2(9.8 m/s²)

h = 392.04 m²/s²/19.6 m/s²)

h = 20 m

Since each floor is 5 m high, so a height of 20 m would be 20 m/5 m = 4 floors.

So, this is 4 floors above Roger's room.

Since roger's room is on the 3rd floor, then 4 floors + 3 floors = 7 floors.

So, the balloon was released from the 7th floor.

Learn more about equations of motion here:

brainly.com/question/27899272

#SPJ1

7 0
2 years ago
The vertices of Figure ABCD are A(1,1), B(2,3) C(4,3) and D(5,1). If Figure ABCD is reflected over the line y = -1, find the coo
Vlad [161]

Answer:

  • <u><em>(2, - 5)</em></u>

Explanation:

<em>The line y = -1 </em>is horizontal: parallel to the y-axis.

The point<em> B (2,3)</em> is above <em>the line y = - 1 </em>at a distance equal to the y-coordinate of B (y = 3) less - 1:

  • Δy = 3 - ( - 1) = 4

When the <em>point B (2,3) </em>is <em>reflected over the line y = -1</em>, the x-coordinate does not change.  The image will be 4 units down the line y = -1, thus the y-coordinate will be - 1 - 4 = - 5.

Hence,<em> the coordinates of the vertex B'</em> are x = 2, y = - 5: (2, - 5).

7 0
3 years ago
Read 2 more answers
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