Answer:
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Step-by-step explanation:
61*40=60*40+1*40=2400+40=2440.
Therefore [] is 4
2/3x - 1/2 = 1/3 + 5/6x....multiply the entire equation by the common denominator of 6...this will get rid of the fractions.
6(2/3x - 1/2) = 6(1/3 + 5/6x) =
4x - 3 = 2 + 5x...subtract 5x from both sides
4x - 5x - 3 = 2...add 3 to both sides
4x - 5x = 2 + 3...combine terms
-x = 5...multiply by -1 to make x positive
x = -5
Answer:
- 891 = 3^4 · 11
- 23 = 23
- 504 = 2^3 · 3^2 · 7
- 230 = 2 · 5 · 23
Step-by-step explanation:
23 is a prime number. That fact informs the factorization of 23 and 230.
The sums of digits of the other two numbers are multiples of 9, so each is divisible by 9 = 3^2. Dividing 9 from each number puts the result in the range where your familiarity with multiplication tables comes into play.
891 = 9 · 99 = 9 · 9 · 11 = 3^4 · 11
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504 = 9 · 56 = 9 · 8 · 7 = 2^3 · 3^2 · 7
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230 = 10 · 23 = 2 · 5 · 23
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<em>Comment on divisibility rules</em>
Perhaps the easiest divisibility rule to remember is that a number is divisible by 9 if the sum of its digits is divisible by 9. That is also true for 3: if the sum of digits is divisible by 3, the number is divisible by 3. Another divisibility rule fall out from these: if an even number is divisible by 3, it is also divisible by 6. Of course any number ending in 0 or 5 is divisible by 5, and any number ending in 0 is divisible by 10.
Since 2, 3, and 5 are the first three primes, these rules can go a ways toward prime factorization if any of these primes are factors. That is, it can be helpful to remember these divisibility rules.
Answer:
the answer is d
Step-by-step explanation:
edginuity