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Westkost [7]
3 years ago
8

Solve absolute value equation. Check for extraneous solution. |2x-3|=2x-1. Post it into the drop box for the unit 2 review.

Mathematics
1 answer:
polet [3.4K]3 years ago
6 0

let's keep in mind that, an absolute value expression is in effect a piecewise one, since it has a ± versions of it.


\bf |2x-3|=2x-1\implies \begin{cases}+(2x-3)=2x-1\\-(2x-3)=2x-1\end{cases}\\\\[-0.35em]~\dotfill\\\\+(2x-3)=2x-1\implies 2x-3=2x-1\implies -3 \ne -1\impliedby extraneous\\\\[-0.35em]~\dotfill\\\\-(2x-3)=2x-1\implies 2x-3=-2x+1\implies 4x=4\\\\\\x=\cfrac{4}{4}\implies x=1

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Is 4y - 8 > 10 true?
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4y-8>10

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4y-8+8>10+8

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