Question

If a vector's magnitude is 36 units right and 33 units up, what's the approximate magnitude of a vector that's one-third the length of the first vector? A. 48.8 B. 16.3 C. 12.2 D. 24.4

Answer 1

Answer:

The correct option is B. 16.3

Step-by-step explanation:

We are given a vector with components

V = 36x +33y

To solve this problem, we find its magnitude

|V| = SQRT (36^2 + 33^2)

|V| = SQRT (2385)

|V| = 48.836

To find the magnitude of the new vector we divide by three the previous quantity

|V2| = 48.836/3 = 16.278