If a vector's magnitude is 36 units right and 33 units up, what's the approximate magnitude of a vector that's one-third the len
gth of the first vector? A. 48.8 B. 16.3 C. 12.2 D. 24.4
1 answer:
Answer:
The correct option is B. 16.3
Step-by-step explanation:
We are given a vector with components
V = 36x +33y
To solve this problem, we find its magnitude
|V| = SQRT (36^2 + 33^2)
|V| = SQRT (2385)
|V| = 48.836
To find the magnitude of the new vector we divide by three the previous quantity
|V2| = 48.836/3 = 16.278
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S = n(a1 + an)/2
2S = n(a1 + an)
2S = na1 + nan
nan = 2S - na1
an = (2S - n a1)/n
Answer:
I would say B because there are 15 1s
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Step-by-step explanation:
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