The data given regarding the alleles are as follows
black(B)-dominant , chocolate(b) - recessive
normal vision - dominant, progressive retinal atrophy - recessive
normal hip joint - dominant, hip dysplasia - recessive
lets first consider one trait
parents are heterozygous
when crossed Bb x Bb
offspring BB Bb Bb bb
--------black----- chocolate
the probability of dogs being black - 3/4
dogs being chocolate - 1/4
likewise for the other two traits
probability of normal vision - 3/4 and retinal atrophy - 1/4
probability of normal hip joint - 3/4 and hip dysplasia - 1/4
we have to calculate the probability of 1st pup being born is
chocolate - 1/4
normal vision - 3/4
normal hip - 3/4
since all these traits should be acquired the probability of having the above three traits is calculated by getting the product of individual probabilities
therefore answer is 1/4 x 3/4 x 3/4
probability = 9/64
Explanation:
A hypothesis is defined as an educated guess , while a research question is simplify a research wondering about the world .
Answer:
Troponin
Explanation:
Myofilaments are found in myofibrils and comprises of thin and thick filaments. Thick filaments are majorly composed of myosin while thin filaments are mainly composed of actin protein.
More specifically thin filament is composed of three proteins known as actin, myosin and troponin. Sarcomere is known as the basic contractile unit and in vertebrates the contraction of striated muscles is mainly controlled by interaction of troponin and tropomyosin on actin filament.
On the stimulation from the nervous system the calcium ions are released from sarcoplasmic reticulum. The tropomyosin filament is moved on actin filament to uncover the surface for the binding of myosin head by the stimulation from calcium ion binding to troponin. This causes the contraction of sarcomere and it continues until the calcium ions are removed from sarcoplasmic reticulum.
Answer:
False. DNA replication in prokaryotes occurs in the cytoplasm, for example
