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garik1379 [7]
3 years ago
10

Find the distance between the points A(2, 3) and B(4, 1).​

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
8 0

Answer:

sqrt(8) units

Step-by-step explanation:

Use the formula d=sqrt((x2-x1)^2 + (y2-y1)^2). d=distance, and (x1, y1) and (x2, y2) are the points.

d=sqrt((4-2)^2 + (1-3)^2)

 =sqrt(2^2 + (-2)^2)

 =sqrt(4+4)

 =sqrt(8)

A and B are sqrt(8) units apart.

kherson [118]3 years ago
6 0

Answer:

sqrt(8) or 2.828

Step-by-step explanation:

You use the distance formula which is sqrt((x2-x1)^2+(y2-y1)^2) where x2 can be either x value

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Answer:

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Step-by-step explanation:

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have a good day

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Alegbra 2: pls help!!
siniylev [52]

Answer:

Sean's rocket lands 3 seconds after Kiara's rocket.

Step-by-step explanation:

Kiara:  f(t)= -16t² + 80t

Sean:  h(t) = -16t² + 120t + 64

Assume that both rockets launch at the same time.  We need to be suspicious of Sean's rocket launch.  His equation for height has "+64" at the end, whereas Kiara's has no such term.  The +64 is the starting height iof Sean's rocket.  So Kiara has a 64 foot disadvantage from the start.  But if it is a race to the ground, then the 64 feet may be a disadvantage.  [Turn the rocket upside down, in that case.  :) ]

We want the time, t, at which f(t) and h(t) are both equal to 0 (ground).  So we can set both equation to 0 and calculate t:

Kiara:  f(t)= -16t² + 80t

0 = -16t² + 80t

Use the quadratic equation or solve by factoring.  I'll factor:

0 = -16t(t - 5)

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We'll choose 5.  Kiara's rocket lands in 5 seconds.

Sean:  h(t) = -16t² + 120t + 64

0= -16t² + 120t + 64

We can also factor this equation (or solve with the quadratic equation):

0 = -8(t-8)(2t+1)

T can be 8 or -(1/2) seconds. We'll use 8 seconds.  Sean's rocket lands in 8 seconds.

Sean's rocket lands 3 seconds after Kiara's rocket.

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2 years ago
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Step-by-step explanation:

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4 0
3 years ago
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answer
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sergeinik [125]

Answer:

53&8

Step-by-step explanation:

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