Answer:
U shaped.
Step-by-step explanation:
When x = 0 , f(x) = 6
when x =1 yf(x) = 0
when x = 2 f(x) = -2
x = 3 f(x) = 0
x = 4 f(x) = 6.
So the graphs falls from the left and rises to the right in the form of a U.
You can draw a rough graph to confirm this.
Answer:
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
By:
I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
Answer:
Step-by-step explanation:
<u>f(x)=0</u>
Domain are the set of x values
f(x)=0 , we find all the x values where y =0
At x intercepts y is always 0
so we find all the x intercepts.
x intercepts are the points where the graph crosses x axis
In the graph we can see that the graph crosses x axis at
<em>-2.5 , -0.75 and 1</em>
<u><em>-2.5 , -0.75 and 1 are the domain where f(x)=0</em></u>