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sveta [45]
3 years ago
5

Choose Yes or No to tell whether each value of p is a solution for this inequality.

Mathematics
1 answer:
blsea [12.9K]3 years ago
6 0
No
THE P IS SOMETHING U NEED TO PLUG IN
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Plz help this is due today NO LINKS OR GROSS PICTURES OR I Will REPORT And please show work
pychu [463]

Answer: Trapezoid

Step-by-step explanation:

Trapezoids are parollelograms, that’s all

6 0
3 years ago
Someone please help?
dybincka [34]

Answer:

42°

Step-by-step explanation:

its 42° because its smaller than 48° and that's the only option smaller lol

5 0
3 years ago
Read 2 more answers
Simplify the following expression into the form a+bi where a and b are rational numbers
hoa [83]

- 28 - 40i

note that i² = (√-1)² = - 1

expand product of factors using FOIL

= - 6 - 6i - 14i - 14i² - 20i + 36i²

= - 6 - 6i - 14i + 14 - 20i - 36

= - 28 - 40i


7 0
3 years ago
How do you do this question?
alina1380 [7]

Answer:

(8√2) / 15

Step-by-step explanation:

A curve bounded by the y-axis is represented by in terms of dy;

\int \:x\:dt

When the curve crosses the y-axis, x will be 0. In this case x is the function of t, so we have to solve for x(t) = 0;

0 = t^2 + 2t --- (1)

Solution(s) => t = 0, t = 2

dy = (1/2 * 1/√t)dt --- (2)

Our solutions (0, 2) are our limits. The area of the curve is in the form A\:=\:\int _b^a\:f\left(t\right)g'\left(t\right)dt , so now let's introduce the limits of integration, x(t) and dy/dt. Remember, dy/dt = (1/2 * 1/√t) (second equation). 1/2 * 1/√t can be rewritten as 1/2 * t^(-1/2)....

A\:=\:\int _2^0\:\left(t^2-2t\right)\left(\frac{1}{2}t^{-\frac{1}{2}}\right)dt\\\\= \int _2^0\:\left(\frac{1}{2}t^{\frac{3}{2}}-t^{\frac{1}{2}}\right)dt\\\\= \left[\frac{t^{\frac{5}{2}}}{5}-\frac{2t^{\frac{3}{2}}}{3}\right]_2^0\\\\= 0\:-\:\left(\frac{4\sqrt{2}}{5}-\frac{4\sqrt{2}}{3}\right)\\\\= \frac{8\sqrt{2}}{15}

Your solution is 8√2 / 15

7 0
2 years ago
Geometric objects can be grouped by their __________.
olga55 [171]
Uhhm since u don't have any choices I'll say shapes
6 0
3 years ago
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