The house number if two adjacent homes are two consecutive even numbers. If their sum is 406, find the house numbers.

Help solve these algebraic fractions please with explanation would be great <3

sineoko [7]

Answer:

7/ Ans;

$\frac{x + 2}{ x + 4} \div \frac{ {x }^{2} - 2x - 8}{ {x}^{2} + 2x - 8} \\ \\ \\ \frac{x + 2}{x + 4} \times \frac{ {x}^{2} + 2x - 8 }{ {x}^{2} - 2x - 8} \\ \\ \\ \frac{x + 2}{x + 4} \times \frac{(x - 2)(x + 4)}{(x - 4)(x + 2)} \\ \\ \\ =1 \times \frac{x - 2}{x - 4} \\ \\ \\ = \frac{x - 2}{x - 4}$

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9/Ans;

$\frac{ {x}^{2} - 9}{ {x}^{2} - 6x + 9} \div \frac{x + 4}{x - 3} \\ \\ \frac{ {x}^{2} - 9 }{ {x}^{2} - 6x + 9} \times \frac{x - 3}{x + 4} \\ \\ \\ \frac{(x + 3)(x - 3)}{(x - 3)(x - 3)} \times \frac{x - 3}{x + 4} \\ \\ \\ = \frac{(x + 3)}{1} \times \frac{1}{(x + 4)} \\ \\ \\ = \frac{x + 3}{x + 4}$

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In the two questions, we first replace the division with multiplication with flipping the fraction after the division sign, secondly we analyze any equation that needs analysis to simplify it, thirdly, to simplify the fraction by deleting the numerator and the similar denominator .

5 0

2 years ago

One eighth of forty eight

Aloiza [94]

One eighth of forty eight is six

Hope I got it right for your sake.

3 0

3 years ago

Read 2 more answers

an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor

Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

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We suppose that tree diameters are normally distributed with mean 8.8 inches and standard deviation 2.8 inches.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

Mean of 8.8 inches, thus $\mu = 8.8$ .
Standard deviation of 2.8 inches, thus $\sigma = 2.8$ .

The interquartile range(IQR) is the difference between the 75th and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = -0.675(2.8)$

$X = 6.91$

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = 0.675(2.8)$

$X = 10.69$

The IQR is:

$IQR = 10.69 - 6.91 = 3.78$

What is the diameter, in inches, of the smallest tree that is an outlier?

The diameter is 1.5IQR above the 75th percentile, thus:

$10.69 + 1.5(3.78) = 16.36$

The diameter of the smallest tree that is an outlier is of 16.36 inches.

A similar problem is given at brainly.com/question/15683591

3 0

2 years ago

Equations and inequalities

DerKrebs [107]

Inequalities and equations use similar steps to solve, but inequalities give a range of numbers that can represent the variable while an equation will give a direct answer.

Example:

4+5x=24

First you would subtract 4 or add the opposite of 4 from 24.

4+5x=24
+(-4) +(-4)
—————
5x=20

Then divide each side by 5 or multiply each side by the reciprocal of 5 to isolate the variable.

1/5*5x=20*1/5 (reciprocal)
X= 4

You would use the same steps in an inequality but end up with a different sign.

8 0

2 years ago

Read 2 more answers

Which explanation best describes how to solve this problem?

Minchanka [31]

I believe it is a but i will double check and post ok

4 0

3 years ago