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Scilla [17]
3 years ago
11

Jason poured 1 gallon 1 quart of water into an empty 2-gallon bucket. How much more water can be added to reach the bucket's 2-g

allon capacity?
Mathematics
1 answer:
Romashka [77]3 years ago
6 0

Answer: 3 quart

Step-by-step explanation:

Given

Jason poured 1 gallon 1 quart of water into an empty 2 gallon bucket

1 gallon can be written as 4 quart

So, 2 gallon can be written as 8 quart

Subtract 1 gallon 1 quart(5 quart) from 2 gallon(8 quart) to get the volume added

\Rightarrow 8-5\\\Rightarrow 3\ \text{quart}

So, 3 quart of water must be added to reach 2 gallon capacity.

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xenn [34]

Answer:

C'=(-1,0)

B'=(-2,1)

A'=(-4,1)

D'=(-4,0)

Step-by-step explanation:

each point moves 3 right and 4 down ( follow the pattern)

Hope i helped :)

6 0
3 years ago
The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
Extra points to the brainiest answer!
mixer [17]

Answer:

Step-by-step explanation:

That'd be the second root of 7^3, where 3 is the exponent of the radical.

6 0
3 years ago
Read 2 more answers
If you get a check for $289.25 a week, how much will you have made it at the end of the month
ankoles [38]
1,157 a month has approximate of 4 weeks so
289.25 x 4 = 1,157
4 0
3 years ago
Read 2 more answers
PLEASE HELP IMMEDIATELY!!
-Dominant- [34]

Answer:

B

Step-by-step explanation:

45-45-90

find hypotenuse: leg × root 2

8 \times  \sqrt{2}

4 0
3 years ago
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