Answer:
m∠1= 79
Step-by-step explanation:
What we have here is two vertical lines and one intersecting point.
The m∠1 and m∠6 are vertical angles, which means that they equal to each other. So, the equation would be: 6x+25= 10x-11.
Step 1- Subtract 6x to both sides.
6x+25= 10x-11
-6x -6x
25= 4x-11
Step 2- Add 11 to both sides.
25= 4x-11
+11 +11
36= 4x
Step 3- Divide both sides by 4.
<u>36</u>= <u>4x</u>
4 4
x= 9
Now that we know the value of the variable x, substitute it into the equation for m∠1.
m∠1= 10(9)-11
m∠1= 90-11
m∠= 79
<u>Check </u>
m∠6= 6(9)+25
m∠6= 54+25
m∠6= 79
Since m∠1 and m∠6 are vertical angles, they should equal each other.
Answer:
KL = 27
JK = 16
MK = 30
NL = 23
m∠JKL = 132°
m∠KLJ = 22°
m∠KMJ = 54°
m∠KJL = 26°
Step-by-step explanation:
The given parameters of the quadrilateral JKLM are;
JM = 27, ML = 16, JL = 46, NK = 15, KLM = 48, JKM = 78, MJL = 22
Taking the sides as parallel, we have that quadrilateral JKLM is a parallelogram
Therefore;
KL = JM = 27
JK = ML = 16
m∠KLJ = m∠MJL = 22°
MN = NK = 15
MK = MN + NK = 15 + 15 = 30
NL = JL/2 = 46/2 = 23
m∠KJM = m∠KLM = 48°
m∠KJL = m∠KLM - m∠MJL = 48° - 22° = 26°
m∠KML = m∠JKM = 78°
m∠MKL = 180° - m∠KML - m∠KLM = 180° - 78° - 48° = 54°
m∠MKL = 54°
m∠JKL = m∠JKM + m∠MKL = 78° + 54° = 132°
m∠KMJ = m∠MKL = 54°
Slope intercept form: y = mx + b
Equation: 682 = 40x
Slope = 40 (or 40/1)
Y-intercept = 0
In this case,
y = the total
x = the amount of minutes
y-intercept = 0, since there isn’t a b in the equation.
slope = 40, because y = mx + b is 682 = 40x
This should be correct, unless there is missing information in the question.
It’s is greater it would only be equal if you multiplied it by 100
