The lengths, in centimeters, of nine earthworms are shown below. 3, 4, 5, 5, 6, 7, 8, 9, 10 What is the median of the data?
mel-nik [20]
The median of the problem is 6 because it is in the middle of the number set of the earthworm sizes.
Answer:
Step-by-step explanation:
The solid is a cuboid with length of 6 inches, a width of 3 inches, and a height of 2 inches.
The volume is l× w×h = 6×3×2 = 36inches^3
Therefore, the following statements are true about the Solid
1) The volume of the solid is 36 in.3.
2) The perimeter of one of its faces is 10 inches.(2width + 2 height = 2×2 + 2×3 = 10 inches)
3) The area of one of its faces is 6 inches^2. (width × height = 3×2 = 6 inches)
4) The area of one of its faces is 12 in.2.(length × height = 6×2 = 12 inches^2)
Given that the area is equal to twice the perimeter and the dimensions are:
length=4x ft, width=(x+6) ft
the perimeter will be:
P=2(L+W)
P=2(4x+(x+6))
P=2(4x+x+6)
P=2(5x+6)
P=(10x+12)
Area of the rectangle is:
A=4x(x+6)
A=4x²+24x
but:
2P=A
thus
2(10x+12)=4x²+24x
20x+24=4x²+24x
thus
4x²+4x-24=0
x²+x-6=0
x²-2x+3x-6=0
x(x-2)+3(x-2)=0
(x-2)(x+3)=0
thus the answer is:
x=-3 or x=2
thus
length=4x=4*2=8 ft
width=(x+6)=(2+6)=8 ft
Depending on what type of problem your looking for
Ex: units, rates, number lines
Srry don’t really have one in mind
Answer:
I thought It was 40%
Step-by-step explanation:
not 100 percent sure on it tho'-'
