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Vedmedyk [2.9K]
3 years ago
6

A photographer shines a camera light at a particular painting forming an angle of 40° with the camera platform. If the light is

58 feet from the wall where the painting hangs, how high above the platform is the painting?
Mathematics
1 answer:
krek1111 [17]3 years ago
4 0

Answer:

Let y be the height above the camera platform of the painting.

tan (40degrees) = y/58

y = 58[tan(40)] = 58(0.8391) = 48.67 feet.

y = 48.67 feet

Step-by-step explanation:

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