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AlekseyPX
3 years ago
6

Find the equation of the line using the info given and write the answers in slope – intercept form.

Mathematics
2 answers:
Fittoniya [83]3 years ago
8 0

Step-by-step explanation:

<u>Step 1:  Find the slope of the new line</u>

To find the slope of a line perpendicular, you need to find the opposite reciprocal.  Which means that you flip the sign and put the number over 1.

Opposite → y = -3 → y = 3

Reciprocal → y = 3 → y = \frac{1}{3}

<u>Step 1:  Find the line</u>

<u />(y-y_0) = m(x - x_0)

(y - 5) = \frac{1}{3}(x - 2)

y - 5+5 = \frac{1}{3}x-\frac{2}{3}+5

y=\frac{1}{3}x+\frac{13}{3}

Answer:  y=\frac{1}{3}x+\frac{13}{3}

Murrr4er [49]3 years ago
4 0

Answer:

y - 5 = 0(x - 2)

y - 5 = 0

y = 5

Step-by-step explanation:

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Please help me i dont understand it
omeli [17]

Answer:

B

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Write an absolute value inequality that has 3 and -5 as two of its solutions
tino4ka555 [31]
Absolute value makes all things inside positive (make result positive)
so one example is
|x+1|=4
so if you had 3 in it woul dyhave
|3+1|=4
|4|=4
4=4
true

if -5
|-5+1|=4
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treu
8 0
2 years ago
Simplify
melomori [17]

Answer: 4\sqrt{3}

Step-by-step explanation:

For this exercise it is important to remember the following:

i=\sqrt{-1} \\\\i^2=-1

Given the following expression:

-2i\sqrt{-12}

You can notice that the radicand (the number inside the square root) is negative. Therefore, in order to simplify the expression, you need to follow these steps:

1. Replace \sqrt{-1} with i and simplify:

(-2i)(i)\sqrt{12}=-2i^2\sqrt{12}=-2(-1)\sqrt{12}=2\sqrt{12}

2. Descompose 12 into its prime factors:

12=2*2*3=2^2*3

3. Substitute into the expression:

=2\sqrt{2^2*3}

4. Since \sqrt[n]{a^n}=a, you can simplify it:

=(2)(2)\sqrt{3}=4\sqrt{3}

4 0
2 years ago
-3 + n = 6n + 22 ; Solve for n.
anygoal [31]

Answer:

-3 + n = 6n + 22

-1n on both sides

-3=5n+22

-22 on both sides

-25=5n

divided by 5

-5=n

Step-by-step explanation:

6 0
2 years ago
Quadrilateral ABCD has the following
a_sh-v [17]

Answer:

No because the angle of point C is NOT congruent to the angle of point A.

Step-by-step explanation:

A quadrilateral MUST be a parallelogram if it has both pairs of its opposite angles congruent.

4 0
2 years ago
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