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Whitepunk [10]
3 years ago
10

Newton observed the action of a prism on white light and on red light. Because he

Physics
1 answer:
konstantin123 [22]3 years ago
3 0

Hey

It was REFLECTIVE on him

Im sure thats the answer.

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I have 510 missing assignments on edg, Any tips on catching up?
RSB [31]

Answer:

Take notes

Explanation:

Cuz it helps you stay on task

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3 years ago
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A box is being dragged across the floor at a constant speed by a rope pulling horizontally on it. friction is not negligible. id
Elena-2011 [213]

Weight (W), the normal force( N), and the tension force( T )in the string will all be forces operating on the box.

<h3>What is tension force?</h3>

The tension force is described as the force transferred through a rope, string, or wire as opposing forces pull it.

The tension force is applied along the whole length of the wire, pulling energy equally on both ends.

A horizontally pulling rope is dragging a box across the floor at a consistent speed. Friction is significant.

Hence, the force acting on the box will be weight W,  Normal force N, and the tension force T, in the string.

To learn more about the tension force refer to the link;

brainly.com/question/2287912

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2 years ago
Question 14 (1 point)
Karo-lina-s [1.5K]

Answer:

car travel

precipitation

O temperature

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Jet streams which is the ability of the object to move at a high speed due to its power is common among some given set of objects. Some are powered by the objects fuel while others are entirely different.

The above given options are actually affected by the jet streams.

5 0
3 years ago
The kinetic energy of an object with a mass of 6.8 kg and a velocity of 5.0 m/s is J. (Report the answer to two significant figu
abruzzese [7]

Answer:

\boxed{\sf Kinetic \ energy \ (KE) = 85 \ J}

Given:

Mass (m) = 6.8 kg

Speed (v) = 5.0 m/s

To Find:

Kinetic energy (KE)

Explanation:

Formula:

\boxed{ \bold{\sf KE =  \frac{1}{2} m {v}^{2} }}

Substituting values of m & v in the equation:

\sf \implies KE =  \frac{1}{2}  \times 6.8 \times  {5}^{2}

\sf \implies KE = \frac{1}{ \cancel{2}}  \times  \cancel{2} \times 3.4 \times 25

\sf \implies KE =3.4 \times 25

\sf \implies KE = 85 \: J

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4 years ago
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Select the correct answer.
Roman55 [17]

Answer:

really think I can see you soon then you can do to

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3 years ago
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