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Artyom0805 [142]
3 years ago
11

An engineer is adding a heat sink to a motor to help absorb some of the heat produced by the motor. Which piece of metal would a

bsorb the MOST heat?
Physics
2 answers:
astraxan [27]3 years ago
6 0
<span>The metal that  would absorb the MOST heat is Copper. </span>Copper is used in heat sink because it has many advantageous properties for thermally effective and long lasting heat converters..Copper is an excellent conductor of heat. It's high thermal conductivity allows heat to pass through it quickly. <span>Aluminium heat sinks are used as a cheaper, lightweight substitue to copper heat sinks, but they have a lower thermal conductivity than copper.</span>
soldi70 [24.7K]3 years ago
3 0

Answer:

2.0 kg of brass is the answer

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The correct answer is this one: "D) significantly more than 100 billion gallons ." Clouds dump around 100 billion gallons of water on rainforests each year. The amount of  rain is evaporated from the rivers, lakes and surface of rainforests each year is significantly more than 100 billion gallons<span> </span>
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71

Explanation:

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A typical male sprinter can maintain his maximum acceleration for 2.0 s, and his maximum speed is 10 m/s. After he reaches this
baherus [9]
20 characters longer later and woah
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3 years ago
In a particular case of an object in front of a spherical mirror with a focal length of +12.0 cm, the magnification is +4.00.(a)
salantis [7]

Answer:

9 cm

-36 cm

Explanation:

u = Object distance

v = Image distance

f = Focal length = 12

m = Magnification = 4

m=-\frac{v}{u}\\\Rightarrow 4=-\frac{v}{u}\\\Rightarrow v=-4u

Lens equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{12}=\frac{1}{u}+\frac{1}{-4u}\\\Rightarrow \frac{1}{12}=\frac{3}{4u}\\\Rightarrow u=9\ cm

Object distance is 9 cm

v=-4\times 9=-36\ cm

Image distance is -36 cm (other side of object)

7 0
3 years ago
he electronics supply company where you work has two different resistors, R1 and R2, in its inventory, and you must measure the
Paraphin [41]

Answer:

R₁ = 50.77 Ω

Explanation:

Since, we know that:

Electric Power = P = VI

but from Ohm's Law:

V = IR

(or) I = V/R

Therefore,

P = V²/R

(OR) R = V²/P

where,

V = Battery Voltage

R = Resistance of combination

FOR SERIES COMBINATION:

R = Rs = (57 V)²/48 W

Rs = 67.69 Ω

but, we know that:

Rs = R₁ + R₂

R₁ + R₂ = 67.69 Ω

R₁ = 67.69 Ω - R₂  __________ eqn (1)

FOR PARALLEL COMBINATION:

R = Rp = (57 V)²/256 W

Rp = 12.69 Ω

but, we know that:

Rp = (R₁R₂)/(R₁ + R₂) = 12.69 Ω

using eqn (1) and value of R₁ + R₂, we get

Rp = 12.69  = R₂(67.69 - R₂)/67.69

859.08 = 67.69 R₂ - R₂²

R₂² - 67.69 R₂ + 859.08 = 0

Solving this quadratic equation we get the answers:

Either, R₂ = 50.76 Ω

Either, R₂ = 16.92 Ω

Since, it is stated in the question that R₁ > R₂. Therefore, we choose the second value. So,

<u>R₂ = 16.92 Ω</u>

using this value in eqn (1), we get:

R₁ = 67.69 Ω - 16.92 Ω

<u>R₁ = 50.77 Ω</u>

4 0
2 years ago
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