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2 years ago

15

Craig Terrill has many _________. Press enter to interact with the item, and press tab button or down arrow until reaching the S

ubmit button once the item is selected A uniforms B opinions C skills D debts

1 answer:

iren2701 [21]2 years ago

7 0

Answer:

is there anything that is a hint? like a picture or a story?

Explanation:

You might be interested in

Really easy it's physics.

iragen [17]

I think it’s B because we aren’t looking for Vf

4 0

2 years ago

Read 2 more answers

In a hydraulic lift, if the pressure exerted on the liquid by one piston is increased by 100 N/m2 , how much additional weight c

shepuryov [24]

Answer:

The additional weight and mass needed for lifting the other piston slowly is 2500 N and 254.92 kg, respectively.

Explanation:

By means of the Pascal's Principle, the hydraulic lift can be modelled by the following two equations:

Hydraulic Lift - Before change

$P = \frac{F}{A}$

Hydraulic Lift - After change

$P + \Delta P = \frac{F + \Delta F}{A}$

Where:

$P$ - Hydrostatic pressure, measured in pascals.

$\Delta P$ - Change in hydrostatic pressure, measured in pascals.

$A$ - Cross sectional area of the hydraulic lift, measured in square meters.

$F$ - Hydrostatic force, measured in newtons.

$\Delta F$ - Change in hydrostatic force, measured in newtons.

The additional weight is obtained after some algebraic handling and the replacing of all inputs:

$\frac{F}{A} + \Delta P = \frac{F}{A} + \frac{\Delta F}{A}$

$\Delta P = \frac{\Delta F}{A}$

$\Delta F = A\cdot \Delta P$

Given that $\Delta P = 100\,Pa$ and $A = 25\,m^{2}$ , the additional weight is:

$\Delta F = (25\,m^{2})\cdot (100\,Pa)$

$\Delta F = 2500\,N$

The additional mass needed for the additional weight is:

$\Delta m = \frac{\Delta F}{g}$

Where:

$\Delta F$ - Additional weight, measured in newtons.

$\Delta m$ - Additional mass, measured in kilograms.

$g$ - Gravitational constant, measured in meters per square second.

If $\Delta F = 2500\,N$ and $g = 9.807\,\frac{m}{s^{2}}$ , then:

$\Delta m = \frac{2500\,N}{9.807\,\frac{m}{s^{2}} }$

$\Delta m = 254.92\,kg$

The additional weight and mass needed for lifting the other piston slowly is 2500 N and 254.92 kg, respectively.

3 0

2 years ago

In a hydraulic garage lift, the small piston has a radius of 5.0 cm and the large piston has a radius of 1.50 m. What force must

Nikitich [7]

Answer:

222.22 N

Explanation:

r = 5 cm = 0.05 m, R = 1.5 m, f = ? , F = 200,000 N

Use pascal's law

F / A = f / a

F / 3.14 x R^2 = f / 3.14 x r^2

F / R^2 = f / r^2

f = F x r^2 / R^2

f = 200000 x 0.05 x 0.05 / (1.5 x 1.5)

f = 222.22 N

7 0

3 years ago

An AC source drives a sinusoidal current of amplitude I0and frequency ? into an inductor having inductance L and a capacitor hav

lukranit [14]

Answer:

option (D)

Explanation:

In an LC circuit which are connected in series, the current lags by 90 by inductor and current leads by 90 by the capacitor.

So, VL(t) leads IL(t) and Vc(t) lags Ic(t).

5 0

2 years ago

A truck moves 60 kilometers east from point A to point B. At point B, it turns back west and stops 15 kilometers away from point

nata0808 [166]

A truck moves 60 kilometers east from point A to point B. At point B, it turns back west and stops 15 kilometers away from point A.

Displacement=15km east

Distance=60+(60-15)=105km

ans is A. The total distance is 105 kilometers, and the total displacement is 15 kilometers east.

6 0

2 years ago

Read 2 more answers