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For 300 trading days, the daily closing price of a stock (in $) is well modeled by a Normal model with mean $196.99 and stand

KATRIN_1 [288]

Answer:

a) 2.5% b) 84% c) 95% d) D. The more unusual day is if the stock closed below $185 because it has the largest absolute z-score.

Step-by-step explanation:

For a) b) and c) we will use the empirical rule, so, we can observe the image shown below

a) 211.23 is exactly two standard deviation above the mean, so, the probability that on a randomly selected day in this period the stock price closed above 211.23 is 2.35% + 0.15% = 2.5%

b) 204.11 represents exactly one standard deviation above the mean, so, the probability of being below 204.11 is 50% + 34% = 84%

c) The probability of getting a value between 182.75 and 211.23 is 95%, this because 182.75 is exactly two standard deviations below the mean and 211.23 is exactly two standard deviations above the mean.

d) The z-score related to 208 is $z_{1}$ = (208-196.99)/7.12 = 1.5 and the z-score related to 185 is $z_{2}$ = (185-196.99)/7.12 = -1.7, therefore, the more unusual day is if the stock closed below $185 because it has the largest absolute z-score.

5 0

3 years ago

What are the prime factor of 625 a. 25.25 b.1,5,5,5,5 c.5,5,25 d.5,5,5,5

Natalka [10]

d.5,5,5,5. A prime number is a number only divisible by 1 and itself. 1 is not a prime number.

3 0

3 years ago

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A rectangular solid has width w, a length of 7 more than the width, and a height that is equivalent to 15 decreased by 3 times t

dexar [7]

Answer:

For a rectangular solid with:

width = w

length = l

height = h

The volume is equal to:

V = w*l*h

in this case we know that:

width = w.

"length of 7 more than the width"

l = w + 7.

"a height that is equivalent to 15 decreased by 3 times the width."

h = 15 - 3*w

Then the volume will be:

V = w*l*h = w*(w + 7)*(15 - 3w) = (w^2 + 7*w)*(15 - 3*w)

V = ( -3*w^3 + 15*w^2 + 105*w - 21*w^2)

V = (-3*w^3 - 6*w^2 + 105*w)

Now, the maximum volume will be for the value of w such that:

V'(w) = 0.

and:

V''(W) < 0

Where:

dV/dw = V'(w).

dV'/dw = V''(w)

Then first we need to differentiate the equation for the volume.

V'(w) = dV/dw = ( 3*(-3*w^2) + 2*(-6*w) + 105)

V'(w) = -9*w^2 - 12*w + 105.

Then we need to find the solution for:

-9*w^2 - 12*w + 105 = 0.

We can use the Bhaskara formula, and we will get:

$w = \frac{+12 +-\sqrt{(-12)^2 - 4*(-9)*105} }{2*-9} = \frac{+12 +- 62.6}{-18}$

Then the two solutions are:

w₁ = (+12 - 62.6)/(-18) = 2.81

w₂ = (+12 + 62.6)/(-18) = -15.5

But we can not have a negative width, so we can just discard the second solution.

Now let's check the second condition for the maximum, we must have:

V''(2.81) < 0.

V'' = dV'/dw = 2*(-9*w) - 12 = -18*w - 12

V''(2.81) = -18*2.81 - 12 = -62.58 < 0 .

Then the volume is maximized when w = 2.81, and the maximum volume will be:

V(2.81) = (-3*(2.81)^3 - 6*(2.81)^2 + 105*2.81) = 180.1

8 0

3 years ago

[21] Please help. What is the volume of the cooler in cubic inches?

GenaCL600 [577]

Answer:

3,724

Step-by-step explanation: Length x width x height

19 x 14 x 14

19 x 14 = 266

266 x 14 = 3,742

hope this helped :)

6 0

3 years ago

To make copies of blueprints, Vantage Reprographics charges a $5 setup fee plus $3 per copy. Myra can spend no more than $59

Butoxors [25]

Answer:

A.

Myra can make 18 or fewer copies

Step-by-step explanation:

Let n be the no. of copies

The cost:

5 + 3n《59

3n《54

n《18

3 0

3 years ago

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