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Paha777 [63]
3 years ago
7

Solve for a given 2e^a =4b

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
6 0

Answer:

  a = ln(2b)

Step-by-step explanation:

Divide by 2 and take the natural log.

  e^a = (4b)/2 = 2b

  a = ln(2b)

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Complete the missing value/help?
blagie [28]

What it is basically asking is if Y = -4, find the value of x in the equation 6x + 7y = 4x + 4y

To solve this you just need to plug in -4 for y and solve for x

6x + 7(-4) = 4x + 4(-4)

6x - 28 = 4x - 16

Now isolate x by adding 28 to both sides

6x - 28 + 28 = 4x - 16 + 28

6x = 4x + 8

and subtract 4x from both sides

6x - 4x = 4x - 4x + 8

2x = 8

divide both sides by 2

2/2x = 8/2

x = 4

x = 4, y = -2

Answer: (4, - 2)

Hope it helps :)

Bransliest would be appreciated

5 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP
maria [59]

Answer:

First option:  3x^2-5x=-8

Second option: 2x^2=6x-5

Fourth option: -x^2-10x=34

Step-by-step explanation:

Rewrite each equation in the form ax^2+bx+c=0 and then use the Discriminant formula for each equation. This is:

D=b^2-4ac

1) For 3x^2-5x=-8:

 3x^2-5x+8=0

Then:

D=(-5)^2-4(3)(8)=-71

Since D this equation has no real solutions, but has two complex solutions.

2) For 2x^2=6x-5:

 2x^2-6x+5=0

Then:

D=(-6)^2-4(2)(5)=-4

Since D this equation has no real solutions, but has two complex solutions.

3) For 12x=9x^2+4:

 9x^2-12x+4=0

Then:

D=(-12)^2-4(9)(4)=0

Since D=0 this equation has one real solution.

4) For -x^2-10x=34:

 -x^2-10x-34=0

Then:

D=(-10)^2-4(-1)(-34)=-36

Since D, this equation has no real solutions, but has two complex solutions.

3 0
3 years ago
Three vertices of a rectangle have coordinates (3,4), (5,-4), and (-7,-7). What is the y coordinate of the fourth vertex?
erica [24]
- Three vertices of a rectangle have coordinates<span> (–</span>3, 1), (7,1), and (7, –4<span>). ... What are the </span>coordinates<span> of the </span>fourth vertex<span> of the </span>rectangle? A. (–3, –4) B. (–3, –1) C. (7, –3) ... go straight down basically -3<span> there </span>has<span> to be two -</span>3 for<span> x coordinate and two </span>7 for y coordinate<span> ... Mathematics; </span>5<span> points; 37 seconds ago.</span>
8 0
3 years ago
Will mark bianleast
Leni [432]

Answer:

(–5, 5)

Step-by-step explanation:

Start with the x-axis (left and right).

-5 so you go to the left by 5 steps.

Next is y-axis (up and down).

Without moving your spot in -5, you move up by 5 steps.

That is point F.

Tip: (x-axis, y-axis) or (left/right, up/down)

Negative number: Left or Down

Positive number: Right or Up

8 0
3 years ago
If G is the midpoint of FH find FG<br>fg=11x-7 gh= 3x+9
gavmur [86]

Solution:

we are given that

If G is the midpoint of FH,  it mean that

FG=GH

we are also given that

FG=11x-7 ,GH= 3x+9

So we can write

11x-7=3x+9\\&#10;\\&#10;11x-3x=7+9\\&#10;\\&#10;8x=16\\&#10;\\&#10;x=2

So FG=11x-7=11*\frac{1}{2}-7=11*2-7=15


3 0
3 years ago
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