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Vadim26 [7]
3 years ago
13

Please solve with explanation

Mathematics
1 answer:
tekilochka [14]3 years ago
8 0

Answer:

large area: small area = 100:25 = 4:1

Step-by-step explanation:

Mid-Segment of a triangle is always <u>parallel to the third side</u>, and the length of the midsegment is <u>half the length of the third side</u>.

(x₁,y₁) (x₂,y₂) (x₃,y₃): A(-10,30), B(30,50, C(-40,20)

XY = 1/2 AC , YZ = 1/2 AB , ZX = 1/2 BC

X (10,40) , Y (-5,35) , Z (-25,25) : X(x'₁,y'₁), Y(x'₂,y'₂), Z(x'₃,y'₃)

area of triangle by 3 vertices: (x₁,y₁) (x₂,y₂) (x₃,y₃) is

a = abs[x₁(y₂-y₃)+x₂(y₃-y₁)+x₃(y₁-y₂)] / 2  ... this is just a common formula for any triangle

a = abs(-10*30 + 30*-10 + -40*-20) / 2 = 100

a' = abs(10*10 + -5*-15 + -25*5) / 2 = 25

a/a' = 100/25 = 4/1

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Katena32 [7]

Answer:

The amount spent on the refrigerator is $ 800 .

Step-by-step explanation:

Given as :

The amount spent on television = $ 1600

Le The total amount in the account = $ A

so, The amount left in account after spent on television = $ A - $ 1600

The amount spent on refrigerator = \frac{2}{5} × ( A - 1600 )

The amount left in his saving account = \frac{1}{3} × A

Now, According to question

A - ( 1600 +  \frac{2}{5} × ( A - 1600 ) ) =  \frac{1}{3} × A

Or, A -  \frac{1}{3} × A = 1600 +   \frac{2}{5} × ( A - 1600 )

Or, \frac{2}{3} × A = 1600 + \frac{2}{5} × A - \frac{2}{5} × 1600

or,  \frac{2}{3} × A -  \frac{2}{5} × A = 1600 - 640

Or,  \frac{10 - 6 }{15} × A = 960

or,  \frac{4}{15} × A = 960

∴ A = \frac{960\times 15}{4}

I.e A = 3600

So, The amount in the saving account  is $3600

∵ , The amount spent on refrigerator = \frac{2}{5} × ( 3600 - 1600 )

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Hence The amount spent on the refrigerator is $ 800 . Answer

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Step-by-step explanation:

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Answer:

5/18

Step-by-step explanation:

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Each dice has 6 equally like outcomes so possibilities are

(1,1)  (1,2)          (1,3)          (1,4)         (1,5)         (1,6)

(2,1)  (2,2)  (2,3)  (2,4)  (2,5)  (2,6)

(3,1)  (3,2)  (3,3)  (3,4)  (3,5)  (3,6)

(4,1)  (4,2)  (4,3)  (4,4)  (4,5)  (4,6)

(5,1)  (5,2)  (5,3)  (5,4)  (5,5)  (5,6)

(6,1)  (6,2)  (6,3)  (6,4)  (6,5)  (6,6)

Now we look at the pair that has sum equal to 9

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Probability of sum greater than 9 = \frac{6}{36}

Probability of sum 9 or higher = P(sum 9) + P(greater than 9)

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